Using struct in function. Allows me to declare, but wont let me call.

Here is my code..

Code:

---

#include <iostream>
#include <stdlib.h>

int bill(struct info(int id, int pass));
struct info
 {
  int id;
  int pass;
 };

int main(int argc, char *argv[])
{
 
  system("PAUSE");       
  return 0;
}

int bill(struct info(int id, int pass))
 {
 
  info bill;
  {
    bill.id;
    bill.pass;
  }
  for(bill.id=0; bill.id != 123; bill.id++)
    {cout<<"What is your 3 digit id?\n";
    cin>>bill.id;
   
      if(bill.id==3)
      { break;
        return 0;
      }
     
      if(bill.id==123)
        {
        cout<<"ID is correct.";
        }
 
      if(bill.id!=123)
        {
        cout<<"ID is incorrect. Please try again";
        }
    }
    for(bill.pass=0; bill.pass != 321; bill.pass++)
    {
      cout<<"What is your 3 digit password?\n";
      cin>>bill.pass;
      if(bill.pass==3)
        {
        break;
        return 0;
        }
   
      if(bill.pass==321)
        {
        cout<<"Pass is correct";
        }
   
      if(bill.pass!=321)
        {
        cout<<"Pass is incorrect";
        }
    }
 }

---

I want it to ask for the id and password of a user. Declare the struct inside the function but it wont let me call the function with the struct inside of main. Please help.

>> int bill(struct info(int id, int pass));

Try :

int bill(struct info i);

'i' would represent the struct in the function.

If you want to be able to use the struct without explicitly using the keyword "struct", then typedef the struct like this:

Code:

---

typedef struct{
//..
//..
}info;

---

Can you make this alittle bit more clear for me...im really new to struct, and programming in general..