Loop control

I do not understand how to pause my display loop. I thought the second scanf would do the job, but it doesn't. Here is the code

Code:

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  int main ()
{
        int op1;                                        // user input operand1
        int op2;                                        // user input operand2
        char operator;                                // user input operator
        int result;                                        // answer for calculation                                       
        int status;                                        // open or close calculator program

for (status = 0 ;status !='q'; )
        {
        printf("\n\t\tCALCULATOR\n\n");
        printf("  Make your selection by entering 2 numbers\n");
        printf("  and an operator as shown in the form below\n\n");
       
        printf("\ti1 + i2                i1 plus i2\n");
        printf("\ti1 - i2                i1 minus i2\n");
        printf("\ti1 * i2                i1 multiply times i2\n");
        printf("\ti1 / i2                i1 divided by i2\n");
        printf("\ti1 ^ i2                i1 to the power i2\n");
        printf("\ti1 G i2                the greatest common divisor (gcd) of i1 and i2\n");
        printf("\ti1 L i2                the least common multiple (lcm) of i1 and i2\n");
        printf("\ti1 R i2                the square root of one quarter of the sum of i1 and i2\n");
        printf("\ti1 Q i2                quit the calculator program\n\n");
       
        printf("  The above menu lists available operations on the left and a brief explanation\n");
        printf("  on the right.  Use the format of the operations on the left to enter a formula\n");
        printf("  \n");
        printf("Type NUMBER  OPERATOR  NUMBER and press RETURN:\n");
        scanf("%d %c %d", &op1, &operator, &op2);

        switch (operator)
                {
                case '+': result = plus(op1,op2);                break;
                case '-': result = minus(op1,op2);                break;
                case '*': result = multi(op1,op2);                break;
                case '/': result = divd(op1,op2);                break;
                case '^': result = powr(op1,op2);                break;       
                case 'g': result = gcd(op1,op2);                break;
                case 'l': result = lcm(op1,op2);                break;
                case 'r': result = qtrsumroot(op1,op2);        break;
                default: printf("Please re-enter your request\n"); break;
                }
printf("your formula is %d %c %d.  The answer is %d\n\n", op1, operator, op2, result);       

printf("Press any key to reset calculator.  Press Q to quit.\n");
scanf("%c". &status);
        }

}

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thanks for any insight.
Keith

Code:

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scanf("%c". &status);

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[list=1][*] , not . after "%c"[*]%c corresponds to character input but status is int[/list=1]

thanks pinko,
I updated the type of status to char and revised the notation on the scanf line. There must be a logic error. I am thinking that the for(status='0'; status !='q'; ) line at the start of the function will be updated by the scanf line at the end of the function. The loop passes by the scanf. hmmmm....

Salem,
Thank you, I did not realize that the input stream needs to be cleared. I very much appreciate you writing -- taking time to reply. This gives me the direction needed to understand what is going on. Of course I had heard that there are better ways than scanf and that scanf has limits, but I didnt' know exactly what that means nor how it would affect me in this instance.
Thanks again for your direction,
Keith

These changes made a vast improvment in the functionality and operability of the display screen that caused me a problem using scanf. My thanks to SALEM for assisting with specific code and explanations of the nature of the problem using scanf.

Code:

---

int main ()
{
                                       
char status;        // open or close calculator program
char buff[100];          // user input workspace

for (status = 0 ;status !='q'; )
        {
       
        fgets( buff, sizeof(buff), stdin );
        sscanf( buff, "%d %c %d", &op1, &operator, &op2);


        switch (operator)
        {
        }

printf("Press ENTER to reset calculator.  Press Q to quit.\n");
fgets( buff, sizeof(buff), stdin );
sscanf( buff, "%c", &status);
}

}

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Both fgets and sscanf can fail, always check their return values.

-Prelude