Linked List nodes reversal

How do you reverse the nodes in a singly linked list?
Here is the struct and a definition of a function i was working on.

Code:

---

// ptr, passed from main, points to the first node in the linked list
// i think. In this function i'm trying to reverse the list and print
// the 'name' members in each node in the reversed arrangement.

...

struct Elephant {
  string name;
  Elephant* next;
};

...

void reverse_elephant( const Elephant* ptr )
{
 const Elephant *temp[50], *curr, *first;
 int x=0;

 curr = ptr;

 while ( ptr != 0) {
  temp[x++] = ptr;
  ptr = ptr -> next;
  }
 cout << "x= " << x << '\n';
 ptr = curr;

 first = ptr = temp[x];

 for (int i=x-1; i>0; i--){
  ptr =  ptr -> next = temp[x];
  cout << "Name= " << ptr -> name << '\n';
  }

}

---

im lost. I know this is a sorry attempt but i'm out of ideas. Can anyone help?

Have you thought about a more object orientated approach?
Like, a class to manage the list. Say you have LinkedList class, when this class gets some data, it will pass it on to a special type of node (called HeadNode???). HeadNode only knows to pass any data comming to it on the whatever it's myNext pointer is fixed on. At first it will be TailNode. TailNode will know to create a new InternalNode and give it's *this(TailNodes) to the new InternalNode, and return the address of the InternalNode to whoever did the original passing. With this structure you can perform all sorts of tests to decide whether or not to pass data past or place it before InternalNodes. Once they have been sorted, simply walk the list, counting objects as you go, then give each object their respective number. This number can then be used in a loop to iterate them anyway you like. You probably know all this, but I thought I'd post it just in case. I recently learnt about a few different types of linked lists.

Info on this can be found from the link in my signature.

Singly Linked Lists

and

Handled Doubly Linked Lists

specifically.

The Handled Doubly Linked List is something of what NickESP is refering to, and is also a solution to your problem. Refer to the section of the main site regarding classes if you dont fully understand whats happening.

>>How do you reverse the nodes in a singly linked list?
Just go through the list like you're going to delete each node, but reset the pointers instead :-)

Code:

---

NODE *reverse(NODE *list)
{
  NODE *temp;
  NODE *current = list;
  NODE *new_head = 0;

  while (current != 0)
  {
    temp = current->next;
    current->next = new_head;
    new_head = current;
    current = temp;
  }

  return new_head;
}

---