Please help debug

as of now it wont compile..when it did compile it wouldnt work after the user chose 1 or 2 (float or decimal)..any help would be appreciated!

Code:

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#include <stdio.h>

int main()
{
  int choice,num1,num2,ans;
  char choice2;
  float num3,num4,ans2;

  printf( "Enter 1 for integers, 2 for floats, 0 to quit: " );

  while ( ( choice = getchar()  ) != EOF )

    switch ( choice )
      {

      default: printf("Error, invalid key pressed\n");
        break;


      case '1':
        printf( "Enter A to add, S to subtract, D to divide, and M to multiply: ");

        while ( ( choice2 = getchar() != EOF ) )
          switch ( choice2 )
            {
            case 'A': case 'a':
              printf( "Enter integer 1: " );
              scanf( "%d", &num1 );
              printf( "Enter integer 2: ");
              scanf( "%d", &num2 );
              ans = ( num1 + num2 );
              printf( "Answer: %d + %d = %d",num1,num2,ans);
              break;
            case 'S': case 's':
              printf( "Enter integer 1 ");
              scanf( "%d", &num1 );
              printf( "Enter integer 2 ");
              scanf( "%d", &num2 );
              ans = ( num1 - num2 );
              printf( "Answer: %d - %d = %d",num1,num2,ans );
              break;
            case 'D': case 'd':
              printf( "Enter integer 1 ");
              scanf( "%d", &num1 );
              printf( "Enter integer 2 ");
              scanf( "%d", &num2 );
              ans = ( num1 / num2 );
              printf(" Answer: %d // %d = %d",num1,num2,ans);
              break;
            case 'M': case 'm':
              printf(" Enter integer 1 ");
              scanf( "%d", &num1 );
              printf(" Enter integer 2 ");
              scanf( "%d", &num2);
              ans = ( num1 * num2 );
              break;
            }

    case '2':
              printf( "Enter B to add, E to subtract, J to divide, and K to multiply");
              while ( (  choice2 = getchar() )  ) do

                switch ( choice2 )
                  {

                  case 'B': case 'b':
                    printf( "Enter integer 1: " );
                    scanf( "%f", &num3 );
                    printf( "Enter integer 2: ");
                    scanf( "%f", &num4 );
                    ans = ( num3 + num4 );
                    printf( "Answer: %f + %f = %f",num3,num4,ans2);
                    break;
                  case 'E': case 'e':
                    printf( "Enter integer 1 ");
                    scanf( "%f", &num3 );
                    printf( "Enter integer 2 ");
                    scanf( "%f", &num4 );
                    ans = ( num3 - num4 );
                    printf( "Answer: %f - %f = %f",num3,num4,ans2 );
                    break;
                  case 'J': case 'j':
                    printf( "Enter integer 1 ");
                    scanf( "%f", &num3 );
                    printf( "Enter integer 2 ");
                    scanf( "%f", &num4 );
                    ans = ( num3 / num4 );
                    printf(" Answer: %f // %f = %f",num3,num4,ans2);
                    break;
                  case 'K': case 'k':
                    printf(" Enter integer 1 ");
                    scanf( "%f", &num3 );
                    printf(" Enter integer 2 ");
                    scanf( "%f", &num4);
                    ans = ( num3 * num4 );
                    break;
                  }
      }
}

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Code:

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Borland C++ 5.5.1 for Win32 Copyright (c) 1993, 2000 Borland
C:\Personal\School\CS225\temp\case01.c:
Warning W8060 C:\Personal\School\CS225\temp\case01.c 23: Possibly incorrect assignment in function main
Warning W8060 C:\Personal\School\CS225\temp\case01.c 61: Possibly incorrect assignment in function main
Error E2308 C:\Personal\School\CS225\temp\case01.c 98: do statement must have while in function main
Warning W8070 C:\Personal\School\CS225\temp\case01.c 99: Function should return a value in function main
*** 1 errors in Compile ***

Tool completed with exit code 1

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You need to nest your while loops. Otherwise the compiler thinks it's a do/while loop. Just put braces after the while loop.

Here's an example (the braces I refer to are colored red):

Code:

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while ( condition ) {

    /* insert the parts you need repeated here */

}

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And for when you need a do/while loop, here's how you implement it:

Code:

---

do {

  /* insert the parts you need repeated here */
 
} while (condition);

---

In either case (I see that you're trying to use both type of loops), the syntax is wrong.

This shows a fairly complete (on purpose) use of c's control statements.
In c++ you can also add exceptions. Instead of
using scanf("%d", &n) you may subsitute with
call to read_int. Another way is to mess with scanf(" %d", &n)

Code:

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#include <ctype.h>
#include <limits.h>
#include <stdio.h>

#define EXPECTED_INT_ERROR 1
#define OVERFLOW_ERROR 2

int read_int(FILE* stream, int *error_code)
{
    int n = 0;
    int c, m;

    if (error_code != NULL) {
        *error_code = 0;
    }

    /* skip ws */
    while((c = fgetc(stream)) != EOF && isspace(c))
        continue;

    if (isdigit(c)) {
        n = c - '0';
        while((c = fgetc(stream)) != EOF && isdigit(c)
              && (error_code == NULL || *error_code == 0)) {
            m = c - '0';
            if (n > (INT_MAX - m)/10) {
                if (error_code != NULL) {
                    *error_code = OVERFLOW_ERROR;
                }
            }
            n *= 10;
            n += m;
        }
        ungetc(c, stream);
    }
    else if (error_code != NULL) {
        *error_code = EXPECTED_INT_ERROR;
    }

    return n;
}

int main(void)
{
    int n, m;
    int error = 0;

    n = read_int(stdin, &error);
    if (error != 0)
        goto print_error;

    m = read_int(stdin, &error);
    if (error != 0)
        goto print_error;

    printf("n = %d\n", n);
    printf("m = %d\n", m);
    goto quit;

 print_error:
    switch(error) {
    case EXPECTED_INT_ERROR:
        printf("Expected integer\n");
        break;
    case OVERFLOW_ERROR:
        printf("Overflow on input\n");
        break;
    default:
        printf("Unknown error\n");
    }
 quit:
    return 0;
}

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