search for chars

How would you search for second occurence of the same character on the line? For example:

ftp,tcp,SF,attack,smurf

How would you search for 3rd comma (before attack) and save the word 'attack' in the buffer?

~Dmitry

Code:

---

char searchThis[50]="ftp,tcp,SF,attack,smurf";//what to search through
char * pointer=new char[500];//pointer with oversized buffer
pointer=strstr(searchThis,"*,*,*,");//I think the wildcards should work, otherwise just do strstr three times for ","
pointer[0]='\b';//deletes the comma returned in the pointer
strtok(pointer,",");//deletes the comma after the word attack along with everything after it
cout<<pointer<<endl;

---

that should work as far as i know

With character arrays:

Code:

---

  char str[80] = "ftp,tcp,SF,attack,smurf";
  char *p;
  char word[20] = "";

  p = strtok(str,",");
  p = strtok(NULL,",");
  p = strtok(NULL,",");
  p = strtok(NULL,",");
  cout << p << endl;
  strcpy(word,p);
  cout << "word:" << word << endl;

---

Or it's easier with the string type. I don't use it (string type), but I think there is a find() function or something.

all I get is segmentation fault. Any idea what this means?

Code:

---

int comma;
cout << "which comma do you want to find?" << endl;
cin >> comma;

int i;
int commaCounter = 0;
char input[] = "ftp,tcp,SF,attack,smurf";

for(i = 0; i < strlen(input); i++)
{
  if(input[i] == ',')
  {
      counter++;
        if(counter == comma)
        {
          cout << "we're there" << endl;
          cout << "comma number " << comma << " was found at character position " << i + 1 << " in the input ." << endl;
          i = strlen(input);
        }
    }
}

if(counter != comma)
  cout << "not that many commas in the input.  sorry....." << endl;

---