Play Again feature problem

I want to add

Do you want to play again? (y/n):

question to my program..

I wrote the code to take the input, etc..

the only problem is... if he says yes, i have
to restart my whole program ... how do i do that ?

when i said main(), obviously, it says that i can't call
main from the function...

how is this accomplished ?

www.akilla.tk

use a loop

Elaborate please ...


by the way, i already have while inside a while inside a while inside a while.... :-) think if i add one more while, doesn't it screw it up ?

moreover, i am using seperate functions to do seperate things in the program... this playagain feature is also used as a seperate function.. so how do i do it now ?

www.akilla.tk

"screw it up" in the sense ... doesn't it slow it down ?

www.akilla.tk

Code:

---

int main()
{
  char caReplay;

  do
  {
    function (...);
    caReplay = function_n(...);
  }while(caReplay != 'n');

  return 0;
}

---

Break your program up into functions or else methods actually if you are using c++.

Game cGame;
...(loop)
cGame.Sequence(...);
caReplay = cGame.FinalSequence(...);
...

Do something like this, but make it better.

Can I use a goto from one function to go to another place in another function ??


[code]
void askquestion()
{
char answer;
cout << play again (y/n);
cin >> answer;

blah blah blah,
on so and so, goto gamestart
}

main()
{
gamestart:
blah blah blah
blah blah blah
blah blah blah
}

goto..

Wouldn't recommend it. While it is valid code, it doesn't make it very easy to debug should a problem arise.

A while loop is your best bet. Generally most games are written with a main loop that executes as long as the game is running, (as long as the user doesn't end the game). Within this loop your game logic is executed.

Code:

---

#include <iostream>
using namespace std;

string again;

int main()
{
                                        again = "yes";
                                    while (again == "y" || again =="yes") {

//code + crap here

              cout << "Would you like to play again? (y/n)" << endl;
                                cin >> again;
            if(again == "n" || again == "no")
}
cin.get();
return 0;
}

---

something like that is what i think you need