Array of ints

Does anyone know how to pass an array of ints to a function?
i tried

Code:

---

int a[2][2] = { {1, 2}, {3, 4} };
function(a);

void function(int **a) {
  printf("%d\n", a[1][1]);
}

---

and it didn't seem to work.
Any suggestions?

> void function(int **a) {
Should be one of these - choose which is most readable

void function(int a[2][2] ) {

void function(int a[][2] ) {

void function(int (*a)[2] ) {

You could also do:

void function(int a[][])

Right, Salem?

> void function(int a[][])
> Right, Salem?
No, not right.

You can only leave the leftmost [] empty.

I see. You can have:

Code:

---

void function (int arr[]); /* legal */
void function (int arr[][2]); /* illegal */

---

But, doesn't that limit what you can do with something like this?

--Garfield

Seems to work now.
Thanks

void function (int arr[][2]);

This is legal. Nothing wrong with it.

hi,
could anyone pls a complete sourcecode showing how to use the function in main? i tried several versions that didn't work. and how can i pass a pointer to the array, not just a copy of it?

> and how can i pass a pointer to the array, not just a copy of it?
Arrays are always passed as a pointer, you have no choice.

> could anyone pls a complete sourcecode showing how to use the function in main?
See the original poster
  function(a);
is the way