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#include<iostream.h>
//I ONLY NEED THE NUMBERS THAT PROVE TRUE
//IN COMPUTING PYTHAGOREAN THEORM
//X^2 + Y^2 = Z^2
main()
{
int z,x,y;
for (x = 0 ; x <=500;x++)
for ( y = 0; y <=500; y++)
for (z = 0; z <=500; z++)
//I only need the z that proves pythagorean thereom printed
//HELP ME
if ((z*z) == (x*x) + (y*y))
cout<<x<<" + "<<y<<" = "<<z<<"\n";
return 0;
}
The Program is not running properly..its suppossed to output only the possibilities of Z being true which is when x^2 and y^2 are equal to the square of Z...
Copy and paste the program and run it...
the output is not correct
please help me..
The program was correct. The output is what confused you ;)
Code:
int main()
{
int z,x,y;
for (x = 0; x <=500;x++)
for ( y = 0; y <=500; y++)
for (z = 0; z <=500; z++)
if(z != 0 && x != 0 && y != 0)
if ((z*z) == ((x*x) + (y*y)) )
cout<<x<<"^2 + "<<y<<"^2 = "<<z<<"^2 ...because: " << x * x <<" + "<< y * y <<" = "<< z * z <<"\n";
getch();
getch();
return 0;
}
And maybe you don't need three for statements.. only some math :)
the numbers
z=p^2 + q^2
x = p^2 - q^2
y = 2*p*q
are pythagoric for two positive integers p,q (p > q).
(you can prove it yourself using (a+b)^2 = a^2 + 2*a*b + b^2).
As far as I know all pythagoric numbers can be written using some p,q but I haven't proved that yet...