Returning a Tree node back to void main()

ok what im doing here with the code below is searching for a
customers name as you can see once the name is found the ID
and the address of that customer displays ..now how can i return
the node pointer back to void main display all of the customers
details

that way by returning the node pointer i can write out the position
where the customer is found rather thatn writting it out in the
function ........

how do i return a node pointer back to void main ?


char BinaryTree::WordSearch (TreeNode *nodePtr,char* wSearchCustName){

if (nodePtr != 0) {

//Compares the two string word in the tree and the word being searched for
if (strcmp(word,nodePtr->CustName) == 0){
cout <<"ID:" <<nodePtr->code << " ";
cout <<" Word:"<<nodePtr->CustName <<" ";
cout <<" def':"<<nodePtr->CustAdd <<'\n';

return true;
}

//Traverse the left branch, then the right branch
this->WordSearch(nodePtr->leftChild,word);
this->WordSearch(nodePtr->rightChild,word);

}return false;
}

You could either try and return a Nodeptr/NULL back up the stack or pass a pointer to a Nodeptr (Nodeptr**) into the function and assign either the found node or NULL to it after de-referencing it.

Code:

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TreeNode *BinaryTree::WordSearch (TreeNode *nodePtr,char* wSearchCustName)
// Return NULL if not found, or else pointer to node

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