Removing junk from end of string

Hello everyone. I've been working a lot with character arrays lately, but I cant seem to get something right. When I allocate some memory for a string (char *string=new char[256]), it will fill it up with random characters. Then, when I copy part of another string into that one, it will copy over, but it still leaves all of the random junk at the end of the string. I've tried setting the character after the copied string in 'string' to 'NULL' and '\0', but it still just left all the junk in there. So, is there something im missing with this, ive been using character arrays for some time, but just recently ran into this problem. Thanks.

Before working on the string, memset it to nuls:

memset ( array, SIZE, '\0' );

-Prelude

Thanks for the reply. I tried that, but it didnt seem to do anything, heres some source:

char *var=new char[256];
memset (var, 256, '\0' );
cout<<"VARALLOC:"<<var<<endl;

It still prints out all of the garbage, do you know what im doing wrong? Thanks.

Check the prototype for memset.

Just did ;), Well, that fixed it (had to switch the 256 and the '\0'), thanks!

you could also make a loop in order to set each character of the array to NULL.

I do often, I think it improves the understanding of loops and character pointers.

I had also tried the loop, but it didnt seem to work before:

for(i=0;i<256;i++)
{
string[i]=NULL //I also had it string[i]='\0', but it didnt seem to work either
}

I dont know why it wouldnt, thought it was pretty strange.

try using a character pointer and instatiating it to NULL or '\0'