Word Count gone kookoo :)

after manipulating an existing program from a book to get a word count, i get a proper count only if i type a space as a first entry. if i start typing immediately after running this program i get 1 less word in my count. .. and now for the unexpected question........................why ? :)

#include <stdio.h>

#define IN 1 /* inside a word */
#define OUT 0 /* ouside a word */

main()
{
int c, other, word, state;
other = word = 0;
while((c = getchar()) != EOF) {
;
if (c == ' ' || c == '\n' || c == '\t')
state = OUT;
if (state != OUT)
++word;
}
printf("%d \n", word);
}

See if you can find the changes I made and why. (Hints: else if, initializing and testing state)

Code:

---

#include <stdio.h>

#define IN 1 /* inside a word */
#define OUT 0 /* ouside a word */

int main ( void )
{
  int c, word = 0, state = OUT;
  while((c = getchar()) != EOF) {
    if (c == ' ' || c == '\n' || c == '\t')
      state = OUT;
    else if (state == OUT) {
      state = IN;
      ++word;
    }
  }
  printf("%d\n", word);
  return 0;
}

---

-Prelude

the "other" was useless because all spaces, \n's etc get asigned to the "OUT" state .

also you set the state to OUT at the start of program while initializing it.

and yes.. ELSE IF

thanx..