returning a char array

Heya all, i was having a few problems passing a char array back to my program.. is this the way the definition is suposed to look like?

Code:

---

char **Addtxt(char box**)
{
        return box;
}

---

because this does not compile.. also box is declaired like so..

box[11][11];

What is the reason for the double indirection operator after the variable name?

Code:

---

(char box**)

---

is that not just another way to say?

Code:

---

box[][]

---

Not to my knowledge.

The indirection operator is used like this:

Code:

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int i1;
int *i2; //declares i2 as a pointer to an int
i1=6;
i2=&i1;
*i2=5;  //since i2 is a pointer, the * in this case dereferences it and assigns 5 as the value held at that memory address.
printf("%d",*i2);

---

I've never heard of using * to represent elements of an array.

presumably box will be manipulated in some way in Addtxt(), so you want the changes to be available in the function that called Addtxt(). You might be happy to know that just the act of sending the array as an argument to Addtxt() allows all that to happen and that you don't need to return anythingl.

void Addtxt(char ** box)

Write instead

Code:

---

char** box

---

But you should consider using std::string in <string>

If you have

box[11][11];

The correct prototype is
void Addtxt(char box[11][11]);

Which you declare as
void Addtxt(char box[11][11]) {
// your code
}


Which you call as
Addtxt( box );

And when you return from the function, the array will have been updated by the Addtxt() function

















PS
You can also write
void Addtxt(char box[][11]);
void Addtxt(char (*box)[11]);
All three variations mean the same thing, but the first is a simple copy/paste

wait, let me get this straight. you have a global function that is outside main() and you want it to edit an array? I don't get what you're trying to do there but here are my solutions:

solution 1:
make the array global so it can be accessed by all functions.

solution 2:
make the variable reference ( if it's inside main() ) and also a pointer (since it is an array).
can this help?
void function_name ( &*array_variable_name )
{
//add your code here
}

thanks guys for all your help here :D,

Quote:

---

so you want the changes to be available in the function that called Addtxt(). You might be happy to know that just the act of sending the array as an argument to Addtxt() allows all that to happen and that you don't need to return anythingl.

---

I did not know about this, thanks for the info!! :D

This is just a thought:

char **Addtxt(char box**)
{
return box;
}

My understanding of this function is to add some text to a character array, which is in theory a character pointer, is it not?

Therefore, since I was doing something similar recently I have a solution which might come in handy later on.

Here is my solution:
Open the attachment and compile, you shall see
It adds the box to itself.

I think that is what you want the program to do, except maybe add other stuff to box, and not box to itself.

I hope that this will help you.