Casting in C++

Hi there??
How do you convert the following operation from java to C++?


ncols = (int) floor[0].length;

where ncols = number of columns and floor is an array declared as: char floor[20[20];

thankyou.

Atif.

Well the operation will work in C++ except for the .length
Since characters can only hold one letter floor[0]'s length is 1 unless it is empty.
If you want the length of a whole array like for example:

int ncols; //Create
char array[20]; // Variables
strcpy(array, "afewletters"); // Cope a string into the array

ncols = strlen(array); // return length of string in the array

I think this'll work but since i've got no compiler here in school i dont know....

And a question. Why do you cast floor[0].length to int, isnt it an int already?

Hi ?
what i meant was i have a 2d array called floor[20][20] of type char. and i want to cast it, like this: int ncols = (int) floor[0].length;
this is in java how do i convert it to C++??

thanks
Atif.

C++ doesn't have the length() mehtod that Java has so you have to figure it out yourself. As mentioned above, if it's a string you can use strlen() or another common way is:

Code:

---

int length = sizeof( array ) / sizeof( array_type );

// so in your case
int length = sizeof( floor[0] ) / sizeof( char );

---

This only works on static arrays however, trying this on dynamic arrays will result in the size of the pointer divided by the type :(.
If you use Java's ability to have non-rectangular matrices then this gets more difficult.
An easy solution would be to create a data type (struct or class) that has length variables you can easily access and set. Then you could use the same style of code.