I need some help with C

Well guys Im starting with C and Im doing a really simple program, but its giving me some issues Maybe you will be able to help me, thats my code

Code:

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#include <stdlib.h>

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Code:

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#include <stdio.h>
void LimitesLee(int linf, int lsup)
{

printf("Introduzca limite inferior y superior.\n");
scanf("%d",&linf);
scanf("%d",&lsup);
/*if(linf>lsup){
LimitesLee(linf,lsup);
*/
}

void LimitesImprime(int linf, int lsup){
printf("Limites: [%d, %d]",linf,lsup);
}
/*int EnteroAleatorio(){
int a;
rand();
a = rand()
if(a>

return rand();
}

*/int main()
{
int linf = 0;
int lsup = 0;
LimitesLee(linf,lsup);
LimitesImprime(linf,lsup);

system("pause");
return 0;
}

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The prob is that when I set the "linf" and the "lsup" the function LimitesImprime still giving me the 0,0 values instead the values that I set
Thanks for your time I hope you can answer me!

You're sending copies of the variables into your LimitesLee() function so any changes made to those variables in that function are lost when you return from the function. You'll need to use pointers for the parameters if you want to change the variables in the calling function.


Jim

Quote:

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Originally Posted by zetaXX

The prob is that when I set the "linf" and the "lsup" the function LimitesImprime still giving me the 0,0 values instead the values that I set
Thanks for your time I hope you can answer me!

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Passing linf and lsup to the function like that passes their value -- any changes you make to them in LimitesLee() won't have any affect on the variables in main(). This is the usual way arguments are passed in C -- to have the function modify them, you'll need to use pointers. There are plenty of tutorials on this.

Or you could have two separate functions to read linf and lsup, and return the value read. Depends if you want to get your head round pointers.

It is because you are setting the values in the function LimitesLee(..) This function takes copies of the variables it receives - They are 'local' to the scope of the function - your variables -anywhere else, even with the same name will not be affected by anything that happens in your called function. You need to learn about pointers and scope:

"using pointers is one way to have a function modify a variable passed to it"

It's pass-by-value vs. pass-by-pointer.

Here's a debugging session with comments

Code:

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gdb) b 30
Breakpoint 1 at 0x100000e36: file limits.c, line 30.
(gdb) run
Starting program: limits
Reading symbols for shared libraries +............................. done

Breakpoint 1, main () at limits.c:30
30                LimitesLee(linf,lsup);
(gdb) p linf
$1 = 0
/* Print address of linf variable being passed */
(gdb) p &linf
$2 = (int *) 0x7fff5fbffbb4
/* Print address of lsup variable being passed */
(gdb) p &lsup
$3 = (int *) 0x7fff5fbffbb0
/* Step into LimitesLess function */
(gdb) s
LimitesLee (linf=0, lsup=0) at limits.c:6
6                printf("Introduzca limite inferior y superior.\n");
/* Print addresses of function parameters */
(gdb) p &linf
$4 = (int *) 0x7fff5fbffb9c
(gdb) p &lsup
$5 = (int *) 0x7fff5fbffb98
(gdb)

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Notice the addresses are different? Now with pass-by-pointer:

Code:

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(gdb) run
Starting program: limits
Reading symbols for shared libraries +............................. done

Breakpoint 1, main () at limits.c:30
30                LimitesLee(&linf,&lsup);
/* Print addresses being passed */
(gdb) p &linf
$1 = (int *) 0x7fff5fbffbb4
(gdb) p &lsup
$2 = (int *) 0x7fff5fbffbb0
(gdb) s
LimitesLee (linf=0x7fff5fbffbb4, lsup=0x7fff5fbffbb0) at limits.c:6
6                printf("Introduzca limite inferior y superior.\n");
/* Print pointers being passed (addresses) */
(gdb) p linf
$5 = (int *) 0x7fff5fbffbb4
(gdb) p lsup
$6 = (int *) 0x7fff5fbffbb0
(gdb)

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Notice they're now the same?

Meh...too slow.

Quote:

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Originally Posted by jimblumberg

You're sending copies of the variables into your LimitesLee() function so any changes made to those variables in that function are lost when you return from the function. You'll need to use pointers for the parameters if you want to change the variables in the calling function.


Jim

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Could you explain me how should I do it? I mean I know how to use pointers, but where should I place them and in what way should I change the function and main?

The function takes pointers as arguments, and you pass the address of each variable to the function.

Note: this means your scanf call variables will also change, because you will be receiving pointers as function arguments.

You may want to start by studying this tutorial: C pointers.

Jim

in effect, at present you may as well have written this :

Code:

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LimitesLee(0,0);

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You know you cant expect changes to 0,0 to be accesible after the function call