accepting two inputs

Hi,

I am new to C++ and reading through the book. I am trying all the practice problems. Could someone maybe help me out with the first practice problem at the end of chapter 4. I can't figure out how to make the program accept two different inputs. I tried to make one x and one y. But the program I make only asks for the first input.

Here's the problem:

Ask the user for two users' ages, and indicate who is older; behave differently if both are over 100.


Thanks in advance. Sorry for the nooby question.

"The book" is a rather vague reference. However, I presume you mean the one that the site owner wrote, which I have not read (although I would if I got a free copy :) ).

It's impossible to say what you're doing wrong if we can't see your code.

Yes, I mean the one the site owner wrote. Here is how I attempted the problem:

Code:

---

#include <iostream>

using namespace std;

int main()
{
    int x;
    cout << "Enter first age:";
    cin >> x;
    int y;
    cout <<"Enter second age:";
    cin >> y;

    if (x < y)
    {
        cout << "The second person is older:";
    }

    else (x > y)
    {
        cout << "The first person is older:";
    }
}

---

Eh, that looks like it should work (though it does not consider what happens if they are of the same age). Are you running your program in a separate command prompt window?

Perhaps your console window keeps disappearing?
FAQ > Stop my Windows Console from disappearing everytime I run my program? - Cprogramming.com

Corrected your code to show the output. Too see the output w/o this code change, run your exe is dos prompt.

Code:

---

#include <iostream>
#include <conio>

---

Code:

---


using namespace std;

int main()
{
    int x;
    cout << "Enter first age:";
    cin >> x;
    int y;
    cout <<"Enter second age:";
    cin >> y;

    if (x < y)
    {
        cout << "The second person is older:";
    }

    else (x > y)
    {
        cout << "The first person is older:";
    }
    getch();


}

---

Do not use sirama's suggested code unless you have good reason to do so. <conio> and getch are non-standard and unnecessary here.

Quote:

---

Originally Posted by Aratel

Yes, I mean the one the site owner wrote. Here is how I attempted the problem:

Code:

---

#include <iostream>

using namespace std;

int main()
{
    int x;
    cout << "Enter first age:";
    cin >> x;
    int y;
    cout <<"Enter second age:";
    cin >> y;

    if (x < y)
    {
        cout << "The second person is older:";
    }

    else (x > y)
    {
        cout << "The first person is older:";
    }
}

---

---

the portion highlighted in red will not do what you expect.

Thank you :). It worked when I tried else if instead of else. Now, when I try the last part of the problem, to behave differently if they are both over 100, my code is not working using &&. Anyone know why not? I appreciate all the input:

Code:

---

#include <iostream>

using namespace std;

int main()
{
    int x;
    cout << "Enter first age:";
    cin >> x;
    int y;
    cout <<"Enter second age:";
    cin >> y;

    if (x < y)
    {
        cout << "The second person is older:";
    }

    else if (y < x)
    {
        cout << "The first person is older:";
    }

    else (x && y > 100)
    {
        cout << "You are both too old.";
    }
}

---

Quote:

---

Originally Posted by Aratel

Thank you :). It worked when I tried else if instead of else. Now, when I try the last part of the problem, to behave differently if they are both over 100, my code is not working using &&. Anyone know why not? I appreciate all the input:

Code:

---

else (x && y > 100)

---

---

again, this will not work! you cannot have a condition with an else, unless it is an else if.

Quote:

---

Originally Posted by Aratel

Thank you :). It worked when I tried else if instead of else. Now, when I try the last part of the problem, to behave differently if they are both over 100, my code is not working using &&. Anyone know why not? I appreciate all the input:

---

else (x && y > 100)
should be
else if (x > 100 && y > 100)

If you want to include a condition, you must use else if. Else is only for the last statement which is executed if no other if/else if are true.
x && y > 100 does not mean what you think it does.
It means
x != 0 && y > 100
You must be explicit for both sides; one condition cannot cover more one "side".

Thanks again to all for the informative input. I think I got it now. I am now working on the next practice problem, with which I am also having difficulty.

I can't seem to figure out how to get the program to accept two different passwords. Line 9 is the problem. First, I tried:
if (password == "5151" || "51")

Again, thanks for taking the time to respond to my nooby questions :)

Code:

---

#include <iostream>
#include <string>
using namespace std;
int main()
{
    string password;
    cout << "Enter password:" << "\n";
    getline (cin, password, '\n');
    if (password == "5151" || password == "51")
    {
        cout << "Access Granted" << "\n";
    }
    else
    {
        cout << "Access Denied" << "\n";
        return 0;
    }
}

---