To return a double value

Hi everyone! When I take the help of pointers,by keeping the return type of the function as void,the program works fine,but when I try to pass the values to the function and use return type as double.It only displays the interger part,even after typecasting.

Code:

---

#include<stdio.h>
double cal_per(int,int,int);
int main()
{
int a=55,b=66,c=77;
double res;
res=cal_per(a,b,c);
printf("%f\n",res);
return 0;
}
double cal_per(int a,int b,int c)
{
double res;res=(a+b+c)/300.0;
res*=100;
return res;
}


---

It is giving the correct result. 55+66+77/3=66.

Actually the answer was varying from 0.000 to the right answer. So I thought there would be some problem with returning the double value.

The program is fine.

But why:

Code:

---

double res;res=(a+b+c)/300.0;

---

when:

Code:

---

double res = (a+b+c)/300.0;

---

does exactly the same, is easier to read, and more likely to help you debug things when you *don't* initialise them properly?

Oh, and INDENT!

Quote:

---

Originally Posted by shruthi

Actually the answer was varying from 0.000 to the right answer. So I thought there would be some problem with returning the double value.

---

The answer can't vary. C does not use fuzzy logic. You wont get

"2+2 is 5 for large values of 2 and small values of 5"

If it varied, your program had errors. As it stands right now, the program will return 66.0