How to read an 8 bit Raw Image

What I would like to do is read
a raw Image in decimal (8 bits, so value 0 - 255)

The code below is something I have started. When I tested it prints out numbers, letters, and ! ? etc.
I understand I am using char, but I should be getting just numbers.
If I do int it prints -858993460 sixteen times.

Am I missing something or am I using the wrong file opener or is there something else I should be using?

Code:

---

char data[1024];

ifstream inStream;

    inStream.open("test.raw");
    if(inStream.fail())
    {
        cout << "Input file opening failed.\n";
        exit(1);
    }


    while(!inStream.eof())
    {
        inStream >> data[i];
        cout << data[i] << endl;
        i++;
        while(i == 16);
    }

---

Where is "i" even declared, let alone initialized? When you have a variable with no initialization, it's undefined what its starting value will be, depending on what was in that block of memory before. Also, unless it's a volatile variable, line 18 is either useless (if i != 16) or an infinite loop (if i == 16).

This does not show all the code I have in main.

Assume i has been initialize
that while loop i == 16 is for testing.
I want to see what is my first 16 values so the terminal does not exist.

Use unsigned char data[1024];

As for the rest, try to create a complete example for us that compiles. In trying to do this you will likely find your error.

King Mir,

I did your suggestions to do unsigned char data and I still got the same results

It outputs something like this:
‘70X‰Z=!FL[’™kJ’¶

Here is the somewhat the code. To be honest all I was missing is the int main, return, close file, and int i =0

Code:

---

int main(){

int i = 0;
unsigned char data[1024];


ifstream inStream;


    inStream.open("test.raw");
    if(inStream.fail())
    {
        cout << "Input file opening failed.\n";
        exit(1);
    }




    while(!inStream.eof())
    {
        inStream >> data[i];
        cout << data[i] << endl;
        i++;
        while(i == 16);
    }

inStream.close();
return 0;
}

---

static_cast data[i] to int or unsigned int when passing it to cout <<. This is to stop cout from thinking you want to print the glyph, and instead print the integer.

King Mir,

Do you mean first use unsigned char data[1024];
then int a = data[1024]?

I ask this because it gives me the range 0-255 (so far I haven't seen a negative number or higher than 255), but when I print this the values are:
145, 55, 48, 88, 137.....

The problem with is that the value should be similar because it is an image. May be like 145 144 145 145 etc etc using the Huffman Code.

Code:

---

int main(){
int i = 0;
unsigned char data[1024];
 
 
ifstream inStream;
 
 
    inStream.open("test.raw");
    if(inStream.fail())
    {
        cout << "Input file opening failed.\n";
        exit(1);
    }
 
    while(!inStream.eof())
    {
        inStream >> data[i];
        int a = data[i];
        cout << a << endl;
        i++;
        while(i == 16);
    }
 
inStream.close();
return 0;
}

---

I actually meant using the static_cast operator, but that works just as well.

If you're still getting the wrong values, I think your remaining error is elsewhere. Or maybe the values aren't actually wrong.