Beginner Needing Help making change

This is my code so far:

Code:

---

#include <iostream>


using namespace std;


int main(){


int cent;
int quarter = 25;
int dime = 10;
int nickel = 5;
int penny = 1;


cout << "Enter an amount in cents: ";
cin >> cent;
cout << "The amount you entered is: " << cent << " cents\n";
cout << endl;


//This is where I am getting lost
if (cent % quarter)
cout << "Quarters: " << cent << endl;
if (cent % dime)
cout << "Dimes: " << cent << endl;
if (cent % nickel)
cout << "Nickels: " << cent << endl;
if (cent % penny)
cout << "Pennies: " << cent << endl;






system("pause");
return 0;
}

---

I have been having a lot of trouble with this one. I am trying to prompt the user for an amount of change, then determine how many quarters, nickels, dimes, and pennies the entered amount would make. I may have been staring at this for too long the longer I look at this the worse my code becomes. Any help would be greatly appreciated..

Code:

---

#include <iostream>


using namespace std;


int main(){


int cent;
int quarter = 25;
int dime = 10;
int nickel = 5;
int penny = 1;
int solveQ;
int solveD;
int solveN;
int solveP;
int remainQ;
int remainD;
int remainN;


cout << "Enter an amount in cents: ";
cin >> cent;
cout << endl;


cout << "The amount you entered is: " << cent << " cents\n";
cout << endl;


solveQ = cent / quarter;        //Finds # of Quarters
    remainQ = cent % quarter;  //Finds remaining cents
solveD = remainQ / dime;        //Finds # of Dimes
    remainD = remainQ % dime;  //Finds remaining cents
solveN = remainD / nickel;      //Finds # of Nickels
    remainN = remainD % nickel; //Finds remaining cents
solveP = remainD / penny;      //Finds # of Pennies


cout << solveQ << " Quarter(s)" << endl;
cout << solveD << " Dime(s)" << endl;
cout << solveN << " Nickel(s)" << endl;
cout << solveP << " Penny(s)\n" << endl;


system("pause");
return 0;
}

---

It's not 100% right but I believe I am on the right track now

You got the concept wrong. When you try to break something down into smaller parts, you start from the proportionaly largest unit, divide your value by that unit and the quotent is the amount of units needed. The remainer is the one that should be repeatedly checked as the new value, but each time taking into account smaller units until it can't be further broken.

EDIT: Nice, that's better.

solveP = remainD / penny; //Finds # of Pennies is the problem / Solved thanx anyway

Whew my head was not in the right place... but thanx much Reaper

Dividing by one doesn't change the answer.

Does it hurt to ask that you indent your code in the future?

Here is another way to do it:

Code:

---


#include <iostream>

using namespace std;

typedef struct
{
    int quarters;
    int dimes;
    int nickels;
    int pennies;
} change;

change count_change(int amount);

int main()
{
    int amount;
    change change1;
    cout << "How much money do you have (in pennies)? ";
    cin >> amount;
    cin.ignore();
    change1 = count_change(amount);
    cout << "You have " << change1.quarters << " quarters, " << change1.dimes << " dimes, " << change1.nickels << " nickels, and " << change1.pennies << " pennies.";
}

change count_change(int amount)
{
    int quarters, dimes, nickels, pennies;
    change change1;
    quarters = amount / 25;
    amount %= 25;
    dimes = amount / 10;
    amount %= 10;
    nickels = amount / 5;
    amount %= 5;
    pennies = amount;
    change1.quarters = quarters;
    change1.dimes = dimes;
    change1.nickels = nickels;
    change1.pennies = pennies;
    return change1;
}

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By any chance are you reading "Practical C++ Programming"? Cuz that's an exercize in chapter 6...... the chapter i just finished :)