need help understanding basic arrays

Hey everyone..

So i'm adding arrays to the already long-enough list of C concepts that i don't understand. I looked at the tutorial on this site and i've googled for info on arrays; nothing i have read has helped me understand any better so i was hoping someone here could maybe explain what's happening in layman's terms.

To be clear, this is not homework, this is just an example practice question that i don't quite understand..

What is the output of the following program?

Code:

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Int main() {
Int array[5] = {3, 6, 2, 7, 1}
Int I;
 
For (i=0; i<4; i++)
              Array[i] = array[i] + aray[i+1]
For (i=0; i<5; i++)
              Printf(“%d”, array [i]);
Return 0;
}

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now i put this into codeblocks and the output was '98981.' However, i don't understand how. I guess my real question is this: What's going on within the for loops?

Quote:

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Originally Posted by jpatrick

now i put this into codeblocks and the output was '98981.' However, i don't understand how. I guess my real question is this: What's going on within the for loops?

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The last loop just prints the array. Given:

Code:

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int array[5] = {3, 6, 2, 7, 1};

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the last array adds the the value of i and i + 1 so the result you're seeing is 3+6 = 9, 6+2 = 8, 2+7 = 9, 7+1 = 8, 1 is the last value and is unaffected since the first loop only loops while i < 4. Don't know how to explain that differently, hope that made sense.

You have three different spellings of array in here:

Code:

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For (i=0; i<4; i++)
              Array[i] = array[i] + aray[i+1]

---

i do understand better now; I mean, i see how you got the output, at least. i guess i was confusing myself after looking at i=0 so my thought process was something like this: since i=0 then 0+0+1=0...

i know bigH. i was rushing :) sorry lol. but rest assured i fixed it in codeblocks.. i copied and pasted this from a powerpoint.

for more clarification.. here's another example that i can't figure out with the same logic because it is a different type of problem..

Code:

---

int main() {
              int a[] = {8, 1, 6, 3, 5, 7, 2, 4, 10, 9};
              int i;
 
                              for (i=0; i<10; i++)
                              a[i] = a[a[i]-1];
 
              for (i=0; i<10; i++)
                              printf("%d ", a[i]);
 
                              return 0;
}

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i'm not entirely sure what

Code:

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a[i] = a[a[i]-1];

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is asking.

Well, let's break it up into parts. First look at a[i]. When i=0, a[i]=8. So a[0]-1 = 7.

Now we can put that into the entire expression

Code:

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a[0] = a[a[0]-1]
a[0] = a[7]
a[0] = 4

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because 4 is the the value stored at a[7].

i see. so then the next value would be a=1, 1-1=0, and 8 is at the 0 value but it has been replaced by 4? so the second value is 4? is that how it works?

Bingo.

well thanks for the help. i'm pretty sure i understand it now. i'm assuming things might get a little complicated with all the numbers changing so i'll just have to keep track of everything on paper.

i appreciate it