What does MapViewOfFile return?

"MapViewOfFile", does this function map a file into the virtual memory and return the base address of the mapped memory?? If yes, then the following code should output 0X400000, beacuse by default the exe is loaded at this location, but the output is 0X360000. Why?? Also when I try to print out the ImageBase entry in the optional header it prints out 0X400000???

Code:

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#include<iostream>
#include<Windows.h>
#include<stdio.h>
#include<WinNT.h>


int main()
{


HANDLE  hFile,hFileMapping;
LPVOID lpFileBase;


if((hFile = CreateFile(TEXT("c:\\linked list.exe"),GENERIC_READ,FILE_SHARE_READ,NULL,OPEN_EXISTING,FILE_ATTRIBUTE_NORMAL,0)) == INVALID_HANDLE_VALUE)
    std::cout<<"unable to open";

if((hFileMapping = CreateFileMapping(hFile,NULL,PAGE_READONLY,0,0,NULL)) == 0)
{
    CloseHandle(hFile);
    std::cout<<"unable to open for mapping";
}

if((lpFileBase = MapViewOfFile(hFileMapping,FILE_MAP_READ,0,0,0))== 0)
{
    CloseHandle(hFile);
    CloseHandle(hFileMapping);
    std::cout<<"couldn't map view of file";
}

printf("%x\n",lpFileBase);

}

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RTFM

Quote:

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Return value

If the function succeeds, the return value is the starting address of the mapped view.

If the function fails, the return value is NULL. To get extended error information, call GetLastError.

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