Reading file, endianess, int

Hello, everyone

I've wanted to start learning more about C++ after been in C# for about 2years.

So I wanted to do this new project into C++ instead, yet I'm struggling so much with such simple idiotic thing, but I can't wrap my head around.

I have a raw file..

Code:

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41000000000000002A000000F4790100....

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The very thing I want is to get the first 4 bytes and display as a int.
That means, show me "65"

I've tried countless things, but can't in a simple way
and the closest I got was using a for loop... definetly not on the simple side...

Code:

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#include <iostream>
#include <fstream>
using namespace std;
int main()
{
    char b[4];
    std::ifstream f("file",ios::binary);
    f.seekg(0);
    f.read(b,4);
    cout << hex << b;
    return 0;
}

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This displays me "A" thats kinda right, but not what I want
I was expecting atleast 41, or 41000000 or 00000041

I've tried to cast it as (unsigned int)b, but then it display some random hex numbers..

What am I doing it wrong, is there a simple way to do this at all?

In c# i'd just use.
int i = b.ReadInt32();
//b being a binaryreader stream of the file.

Quote:

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Originally Posted by Enzo Maganha

The very thing I want is to get the first 4 bytes and display as a int.
That means, show me "65"

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How are you interpreting those 4 bytes as an int?

Quote:

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Originally Posted by laserlight

How are you interpreting those 4 bytes as an int?

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Gotta to thank ya, since your question did lead me to an answer..

that was using

Code:

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int x;
f.read((char*)&x,4);

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but I think I cheated, as I don't even understand fully what I am doing here..

reading 4 bytes of the file pointed by char into the reference to the int x?

Quote:

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Originally Posted by Enzo Maganha

reading 4 bytes of the file pointed by char into the reference to the int x?

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Basically, you are interpreting those first four bytes as the bytes of an int as it would have been written - endianness aside - by the write member function of an ostream.