How to input char variables in the same line?

I have to make this program: I have to enter x number of letters in the same line and the program has to count vowels and consonants. So I've made a program that does all that except I don't know how to enter the letters in the same line.
P.S. I know this is a basic c++ but couldn't find a better place to post this.

Code:

---

#include <iostream>


using namespace std;


int main()
{
    char letter;
    int vow = 0;
    int con = 0;
    cout << "Enter the letters. To end the input insert a: " << endl;
    do
    {
        cin >> letter;
        if (letter=='a'||letter=='e'||letter=='i'||letter=='o'||letter=='u'||letter=='A'||letter=='E'||letter=='I'||letter=='O'||letter=='U')
        {
            vow++;
        }else
        {
            con++;
        }
    }while(letter!='a');
    cout << "Number of vowels is: " << vow << endl;
    cout << "Number of consonants is: " << con << endl;
    return 0;
}

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So... essentially you want to input a string, say, "Hello World!" and count consonants and vowels?

No, I have to enter random number of letters and the input ends with little letter a, for example:

Input: b i G h e K p a (and when I type in that last letter which has to be "a" it guves me a number of vowels and consonants that I typed in)

Output: Number of vowels is: 3. Number of consonants is: 4.

Then what does letters in the same line mean?

Like I just wrote it.
RIGHT:
Input: b [ENTER] i [ENTER] G [ENTER] ....
WRONG:
Input:
b [ENTER]
i [ENTER]
G [ENTER] ....

... or without having to press ENTER doesn't matter it just has to get letters in the same line and has to end with a letter "a" not "A".

I don't see why it would be unacceptable.
...So, is this unacceptable too:

Input: "Hello World!"
Output: "Invalid input! Try again."
Input "Hello Worlda"
output: OK

You have to input a few letters (not sentences! ... and in the same line) and the input finishes when you enter "a", then you get a number of vowels and consonants as the result.

Have you tried just running what you have, with the input in the format that you expect?

Even if you are reading input character by character, that in no way implies that the format of the input is one character per line.

What I need is when I type in first letter for example "b" and press ENTER to stay in the same line, don't want to go to a new line, even though I don't know if that's even possible.

What you want is not possible in any portable way. Hence, we are asking if it is possible to just lax the requirements.

Quote:

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Originally Posted by Elysia

What you want is not possible in any portable way. Hence, we are asking if it is possible to just lax the requirements.

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You're utterly wrong.

OP, the code already does what you want. To use your example all you have to do is type

b i G h e K p a

And then press enter. The loop will still stop at 'a'. Since cin is line buffered, though, you will have to press enter to get things to happen (that's usually what buffered means -- how many keys you have to press before something happens). You can press enter whenever you're ready. This is what I was trying to say in my earlier post. Just because you read one character at a time, it doesn't mean the characters have to be on separate lines.

Quote:

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Originally Posted by whiteflags

...

OP, the code already does what you want. To use your example all you have to do is type

b i G h e K p a

And then press enter. The loop will still stop at 'a'. Since cin is line buffered, though, you will have to press enter to get things to happen (that's usually what buffered means -- how many keys you have to press before something happens). You can press enter whenever you're ready. This is what I was trying to say in my earlier post. Just because you read one character at a time, it doesn't mean the characters hae to be on separate lines.

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That is what I suggested before, which apparently was "wrong."
A sequence of characters. A sentence is also a sequence of characters.
But apparently it must end with an 'a', so if you enter a series of characters that do not end with an 'a', then what?

Quote:

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That is what I suggested before, which apparently was "wrong."
A sequence of characters. A sentence is also a sequence of characters.

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You have to press when you know you're right.

Quote:

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But apparently it must end with an 'a', so if you enter a series of characters that do not end with an 'a', then what?

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Why don't you know? The loop continues until you do enter an 'a' obviously. If you make several "lines" of input it makes no difference.

Quote:

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Originally Posted by whiteflags

Why don't you know? The loop continues until you do enter an 'a' obviously. If you make several "lines" of input it makes no difference.

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That contradicts what the OP wants.
So my question is still: is it acceptable to just let it wrap around several lines instead of requiring all characters be on a single line?

Quote:

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Originally Posted by whiteflags

You're utterly wrong.

OP, the code already does what you want. To use your example all you have to do is type

b i G h e K p a

And then press enter. The loop will still stop at 'a'. Since cin is line buffered, though, you will have to press enter to get things to happen (that's usually what buffered means -- how many keys you have to press before something happens). You can press enter whenever you're ready. This is what I was trying to say in my earlier post. Just because you read one character at a time, it doesn't mean the characters have to be on separate lines.

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I get what you want to say but when I press "a" the input MUST stop and the program goes to output, in other words, it cannot allow me to input any more letters after "a".

Quote:

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Originally Posted by Lucas525

I get what you want to say but when I press "a" the input MUST stop and the program goes to output, in other words, it cannot allow me to input any more letters after "a".

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Ah... then you have to use unbuffered input, which is not provided by the standard libraries. This FAQ will show you several ways to get an unbuffered character. That way the program ends immediately after pressing 'a'.

Interestingly enough, with what you showed me, concerning something like "pdfjka ifhf" everything after 'a' isn't going to be processed anyway.

I hope I helped.

It's done! getche() was the command I was looking for. So this is the program:

Code:

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#include <iostream>
#include <conio.h>
#include <cstring>


using namespace std;


int main()
{
    char suglasnici [43] = {'b','c','d','f','g','h','j','k','l','m','n','p','q','r','s','t','v','w','x','y','z','B','C','D','F','G','H','J','K','L','M','N','P','Q','R','S','T','V','W','X','Y','Z','\0'};
    char slovo;
    int sam = 0;
    int sug = 0;
    int i;
    cout << "Upisite slova. Za kraj upisite malo slovo a: " << endl;
    do
    {
        slovo = getche();
        cout << " ";
        if (slovo=='a'||slovo=='e'||slovo=='i'||slovo=='o'||slovo=='u'||slovo=='A'||slovo=='E'||slovo=='I'||slovo=='O'||slovo=='U')
        {
            sam++;
        }else
        {
            for(i=0;i<strlen(suglasnici);i++)
            {
                if(slovo == suglasnici[i])
                {
                    sug++;
                }
            }
        }
    }while(slovo!='a');
    cout << "\nBroj samoglasnika je: " << sam << endl;
    cout << "Broj suglasnika je: " << sug << endl;
    return 0;
}

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The variables and texts are all in croatian. I know I could have made the suglasnici(consonants) variable as a string so it would be shorter but it's ok as long as it's working...