char* to string object

Hi,

I am trying to create a string object from a char array.

My char array has "This house is nice"

string tempStr(MyCharArray);

tempStr now has "This", which is wrong!


How can I can put the whole line in my string object? thanks.

I don't know why that is happening but char* isn't an array. Thats a pointer. char blabla[50] is an array

The following code works fine for me. I'm using MSVC++ 6.0, what about you?

Code:

---

#include <string>
#include <iostream>

using namespace std;

int main()
{
    char* MyStringArray = "This house is nice.";
    string tempStr(MyStringArray);
    cout << endl << tempStr << endl;  // Prints out "This house is nice."
    return 0;
}

---

Quote:

---

Originally posted by ErionD
I don't know why that is happening but char* isn't an array. Thats a pointer. char blabla[50] is an array

---

I am aware of the difference. Here's the code snippet:

<code>
nom = new char[50];
char* ptr = &tamp[4]; // location 4 is where the name begins

while (ptr)
{
if (isspace(*ptr) || *ptr == '\0')
nom[i++] = ' ';
else
nom[i++] = *(ptr++);

if (isspace(*ptr) && isspace(*(ptr + 1)))
{
nom[i] = '\0';
string nomm(nom);
prod->setNom(nomm);
break;
}
}
</code>

basically, I am reading a name of a product from a file. The name is multi names separated by space and ended by double spaces.

do you guys know of a way to tokenize on double space?

The code I posted above is ugly and doesn't really do the job. If I use strtok(myStringArray, " "), it will still tokenize on ONE space rather than two spaces.

Thanks for the feedback y'all.

I think your code is flawed, because as soon as it hits a space, ptr is no longer incremented:

Code:

---

if (isspace(*ptr) || *ptr == '\0')
  nom[i++] = ' ';
else
  nom[i++] = *(ptr++);

---

Quote:

---

Originally posted by ErionD
I don't know why that is happening but char* isn't an array. Thats a pointer. char blabla[50] is an array

---

This is actually a tad incorrect. array[50] actually defines a pointer which points to the first item in an array. Example:
char blah[10]="hello";
cout << blah << endl << (blah+1) << endl;

This would produce:
hello
ello

That is why you specify char* when passing an array of character to a function/method, because in actuality it is a pointer to the start of the string.