what's wrong with this if function

Well, this seems to be a bit strange..
this is the simple palindrome code..

Code:

---

# include <stdio.h>

int palindrome (int n)
{ 
  int rev=0, k;
 
  while (n!=0)
  {
      k = n%10;
      rev = rev * 10 + k;
      n = n/10;   
  }
 
  if (rev == n)
    return n;
  else
    return 0;
}

int main (void)
{
  int n=9009;
 
  printf("%d",palindrome(n));
}

---

As we know the input N is palindrome.. but its returning 0..
I checked the value of rev after the calculation ... it went fine.
but when I use this condition
if (rev ==n)
something is going wrong inside..
I checked the value of rev & n values after that .. they get turning to 0;

why ?

where's the little bug, that's hiding?

Notice that at the end of the loop, n == 0. Therefore, for rev == n to evaluate to true, rev must be 0, in which case 0 is returned. Therefore, the function always returns 0.

oops .. got the bug.. its very silly.
n is tending to 0 in the whole iteration .