Display own name

Hello everyone,
I need to do a program that displays its own name.
So that, when I execute the program, let's say example.exe, "example" will be
printed on the screen.
Any ideas?

Thanks in advance

argv[ 0 ] may contain the name of the executable. Look up command line arguments.


Quzah.

quzah's use of the word "may" reflects the fact that the content of argv[0] -if any - is implementation defined. argv[0] may be a NULL pointer. If it is not a NULL pointer, it may yield an empty string (""), the name of an executable, a full path to the executable, or some other representation.

If argv[0] does not contain the name of the executable then the method to obtain it (eg API functions to call) is system dependent.

Quote:

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Originally Posted by grumpy

quzah's use of the word "may" reflects the fact that the content of argv[0] -if any - is implementation defined. argv[0] may be a NULL pointer. If it is not a NULL pointer, it may yield an empty string (""), the name of an executable, a full path to the executable, or some other representation.

If argv[0] does not contain the name of the executable then the method to obtain it (eg API functions to call) is system dependent.

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Thanks for the fast reply. As a matter of fact argv[0] contains the filename, but it is giving me the whole path like c:desktop \bla bla\mypro.exe

I only need the filename. Is there a way to parse only the filename from that ?

Many thanks

Yes, e.g., search for the last '\' and take the part after that.

Quote:

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Originally Posted by laserlight

Yes, e.g., search for the last '\' and take the part after that.

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I am so sorry but I am a newbie, could you please show me how to do this on C?

Take a look at this tutorial It should help you implement what Laser said.

Thank you very much!