What output does it produce?

I am trying to find how do I find what output does it produce?

Code:

---

 
int funA(intx);

int main()
{

int a,b,c;
    a=5;
    b=5;
    c= funA(b);
    printf(%d %d %d,a,b,c);
    return 0;

}

int funA(int m)
{      return m*m;
}

---

When I entered the following information in the complier nothing happens. Should I not enter the following code in the complier

no compiler will compile that code for you. where are the semicolons? and how about including some header file for printf?

My mistake I forgot the semicolons but, with the semicolons it will not compile

Programming languages like C have formal and very specific grammars. If you make any mistakes in the source code, the program will not compile. (As compared to human languages where we "get" what someone is trying to say, even though it may not be grammatically correct!)

You have three mistakes you need to address. The first is the failure to include a required library for the printf statement. The second is the argument in the funA prototype. And the third is the printf statement - the format string needs to be enclosed in quotes.

Having said all that, you should be able to "bench test" the program and step through it yourself and find the answer you're looking for!

Kevin

Quote:

---

Originally Posted by intimidator

I am trying to find how do I find what output does it produce?

---

"Syntax error"

Code:

---


int funA(int x);

int main()
{

int a,b,c;
    a=5;
    b=5;
    c= funA(b);
    printf("%d %d %d\n",a,b,c);

 return 0; 
}   
int funA(int m)
{     
return m*m;
}

---

that should do it

When I try to compile the output camel-man posted I would see the black screen pop up but then it goes off screen and nothing happens.

Before the end of the main function, add

Code:

---

system("PAUSE");

---

Kevin