How to read uint8_t data type from command line input

Hi All,

Here is my simple program

Code:

---

#include<iostream>
using namespace std;
 
int main()
{
uint8_t sa[6];
cout<<"enter addr"<<endl;
 
for(int i=0;i<6;i++)
cin>>sa[i];
 
for(int i=0;i<6;i++)
cout<<"Address sa["<<i<<"]"<<sa[i]<<endl;
 
system("pause");
return 0;
}

---

when i input values from console
12
21
21
22

my array should read
sa[0] 12
sa[1] 21

but instead
it reads
sa[0] 1
sa[1] 2

how can I have these values entered or modify my program to make my sa[0] to have 12 and not a single element

please help me with this
I want to use uint8_t data type only

Thanks to all for reading this post.
Looking forward to your help.

That's because on many systems uint8_t will be a "char". So basically, you're reading a char. I'm not sure if you can modify input streams to read an integer instead, but the easiest is to read it into an integer variable first.

Thanks EVOEx.

I will change inpit stream to integer and then convert to hex . I will then assign it to uint8_t data type.
Hope it works.

Thank you.