Converting command line char *argv[] to int
Hey guys, First off I just want to say awesome site been very helpful.
Anyways, I'm currently running into a problem while trying to convert a command line argument to an int.
I'm running into a problem where I can't convert the data inside argv[1] to an int
example argv[1] = 21231
and it is grabbing the first data "2" representing it as an ascii code "50"
This converts to ascii (If I am correct its because its assigning a char to an int and thus takes it as an ASCII code)
Code:
int number = *(argv[1]);
This creates a runtime error
Code:
int number = atoi(*argv[1]);
TLDR: I'm trying to grab data from *argv[1] and convert it to an int
FULL CODE
Code:
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[]){
//Grab data from Command line arguements
int length = strlen(argv[1]);
int number = atoi(*argv[1]);
int startBase = atoi(*argv[2]);
int convertBase = atoi(*argv[3]);
printf("Argument Amount: %d\n", argc-1);
printf("Number to be converted: %d\n", number);
printf("Base system %d\n", startBase);
printf("Converting to base %d\n", convertBase);
printf("Length %d\n", length);
return 0;
}
Thanks in advance
