Program skipping input....Scanf()

Code:

---



#include <stdio.h>
int _1st, end;
char letter;


int main(void)

{



scanf("%d", &_1st);
scanf("%d", &end);


scanf("%c", &letter);

printf("_1st = %d\n", _1st);
printf("Letter = %c\n", letter);
printf("_2nd = %d\n", end);

printf("\n\n");

system("pause");


}

---

The code above has been causing me a lot of trouble. ANY help would be appreciated.
I am new to C programming, as the code above may indicate, and I want to collect two numbers (the first two scanf()s) and then a letter (the third scanf() ). However, it seems as if the program completely skips the letter step and advances to displaying what was entered, not even giving a chance to enter the letter. What is going on? Is it my compiler or just me?


THE OUTPUT FOR 8 and 20, for example:


8 20
_1st = 8
Letter =

_2nd = 20

Quote:

---

8 20
_1st = 8
Letter =

_2nd = 20

---

scanf leaves a newline in the input, which is being picked up when you read in a character, and this is being printed out. That also accounts for the mysterious blank line between "Letter" and "_2nd".

You can get around this by enforcing some limits on what letter can be:

Code:

---

letter=0;
while (!isprint(letter)) {
    scanf("%c",&letter);
}

---

or something to that effect.

Cprogramming.com FAQ > Validate user input

System pause is not portable. Just input another line.

Also don't forget to return 0; from main.

C Links (no affiliation)
http://cboard.cprogramming.com/c-pro...standards.html
Cprogramming.com FAQ
Category:Programming Tasks - Rosetta Code
Main Page - C
Main Page - clc-wiki

My C Stuff (GPL):
PaperDragon
TML Version 2
Fix missing brackets with Anchor
The Nerd Show | Platypus