Why does my program only stay open like this?

Code:

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#include <iostream>
#include <string>

int main()
{
    std::cout << "Please enter your first name: ";

    std::string yoname;
    std::cin >> yoname;

    std::cout << "Hello, "<< yoname << "!" << std::endl;
    std::cin.ignore();
    std::cin.get();

    return 0;
}

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If I use one or the other (std::cin.ignore() or std::cin.get()) then the program won't stay open. Does it really have to be a combination of the two?

I'm using Code::Blocks 10.05 on Win7 64.

std::cin>> yoname will leave the return key in the input buffer, cin.ignore() will then discard this return key. cin.get() then waits until another return key is pressed.

You could just run the application in terminal, as it is a console app, and see, that it doesn't disappear at all.

Or use whatever method to pause it at the end, just make sure to get rid of it in the final build. ;) You wouldn't want "dir/ls", cd or pwd to have a "press enter to continue" at the end every time, hm?

Quote:

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Originally Posted by scwizzo

std::cin>> yoname will leave the return key in the input buffer, cin.ignore() will then discard this return key. cin.get() then waits until another return key is pressed.

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That assumes the user does not enter any whitespace characters, other than carriage return after the first character input. The behaviour is a little different if there is other whitespace in the input.

As a rough rule, mixing input styles on a particular stream (eg streaming operators then stream's get() function) is not a good idea. Using ignore() can only partially recover from that, particularly if input is not quite what you expect.