for loop and while loop

I need help for this code
i tried but it could give me what i want

what does the following function do?

int fx(char *s) {
int i;
while (*s!= '\0') {
s++;
i++;
}
rturn
}

what is wrong with this code of mine?

int a[10], i, *p;
*p=10;
for(i=10; i>0; i--) a[i] = i*i;
p = a;
printf(%dn\,*(p+4));

Neither has code tags - see the intro threads, edit your post.

what is mean by code tag?

You write this [code]int main(void)[/code] and then it looks like this

Code:

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int main(void)

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I need help for this code
i tried but it could give me what i want

what does the following function do?

int main(void)
int fx(char *s) {
int i;
while (*s!= '\0') {
s++;
i++;
}
rturn
}

what is wrong with this code of mine?

int a[10], i, *p;
*p=10;
for(i=10; i>0; i--) a[i] = i*i;
p = a;
printf(%dn\,*(p+4));

Close :P. Now make sure the code is WITHIN the code tags, in stead of before it. Also, since you have two piece of code, you need two pairs of code tags.

Quote:

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what does the following function do?

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Nothing. It doesn't even compile.

Quote:

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what is wrong with this code of mine?

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'p' is uninitialized - it has to point to an actual variable in memory (heap or stack) before it can be used, naturally. Moreover, if it can't be assigned to one at the point of initialization, then set it to NULL.

http://cboard.cprogramming.com/cplus...ead-first.html
read it NOW

Quote:

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Originally Posted by Gabi

I need help for this code
i tried but it could give me what i want

what does the following function do?

Code:

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int main(void) //what is this line doing here??
int  fx(char *s) { //this is the first line of a function which returns an int
int i; //this creates an integer (hence 'int') but you must initialize it to 0 by adding "= 0" //before the semicolon
while (*s!= '\0') { //this is the first line of a while loop (and says loop while whatever is //being pointed at by the char pointer 's' does not equal a null-terminating character
s++; //this increments the 's' pointer to the next char location in memory
i++; //this increments i
}
rturn //this is supposed to be "return i;" without the quotes
}

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what is wrong with this code of mine?

Code:

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int a[10], i, *p; //what is this????
//Maybe you were trying to do something like this:
//int a[10]; //int array of 10 elements (0 -9)
//int i = 0; //integer initialized to 0
//int *p = &i; //get a pointer to 'i'
*p=10; //dereference the pointer and assign 'i' to 10
for(i=10; i>0; i--) a[i] = i*i; //this is WRONG...
//change to:
//for (i = 9; i > 0; i--) a[i] = i*i; //now you're not trying to access an element of the array
//which doesn't exist
p = a; //assign the pointer the address of the array
printf(%dn\,*(p+4)); //i don't think this is correct...

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Read my comments.