problem with if statement

hello every one
I'm trying to solve this question but i solve it wrong

Write a program to prompt 5 integers from the operator. Find the largest of those 5 integers and display it to the screen.

Sample input-output
Number 1: 8
Number 2: 12
Number 3: 5
Number 4: 22
Number 5: 17
The largest is: 22

this is my solution which is totally wrong

Code:

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#include<stdio.h>

int main(void)

{
 float num1;
 float num2;
 float num3;
 float num4;
 float num5;

         
printf ("inter 5 numbers ");
scanf ("%f%f%f%f%f",&num1,&num2,&num3,&num4,&num5);


if (num1>num2,num3,num4,num5)
         
    printf("\nthe bigger number is %f",num1);
   
  else
 
      if (num1<num2,num3,num4,num5)
     
    printf("\nthe bigger number is %f",num2);
   


      if (num3>num1,num2,num4,num5)
       
    printf("\nthe bigger number is %f",num3);
   
    else
   
    if (num4>num1,num2,num3,num5)
         
    printf("\nthe bigger number is %f",num4);
     

    else 
    printf("\nthe bigger number is %f",num5);
   
   
        getchar();
      getchar();
   
     
    }

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i wont know the right answer

> if (num1>num2,num3,num4,num5)
This doesn't compare num1 with 4 other numbers.

You need
if ( num1 > num2 && num1 > num3 && and so on...

at first i wanna thank u alot about your answer

now the program work fine when i put the value from 1 to 10
but if i put the values such as 33
23
12
54
45
it doesn't work so whats wrong now?

Alternatively, you may want to consider a different solution that does not involve so many if else blocks. Hint: You don't need to remember all the numbers in different variables in order to determine which one is the largest.

how can i solve it using different solution?

You need to remember the greatest number you have read so far each time you read another number. However, that number you can read can be stored in a single variable. All you need are two variables:

nr - the number currently read
max - the greatest number so far

Then check if the number you have just read is bigger than what you had as max so far.

Use a for() loop and two variables, one for the input and one as a sort of "high score". The first time thru (you could also do this before the loop), you set the high to the input. Thereafter, if the input is higher than the high, you set the high to the input.

At the end, the high value will be the highest number entered.

I see great minds think alike claudiu ;)

Quote:

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Originally Posted by MK27

I see great minds think alike claudiu ;)

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Yes, this was a real tough one to figure out ;).

But hey, if this was my first time programming I would be using the 5 number method as well :), it just makes sense for someone who doesn't divide his whole life in small algorithmic steps.

Yeah, the more you code the more you think that way. I even brush my teeth in an iterative loop. :D

Would a lisp programmer have 32 brushes working in his mouth? :D

That might explain the "lisp smile":

Code:

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((((((((((((((((((((((  )))))))))))))))))))))))

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LOL it would look like:

Code:

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(toothpaste
 (toothbrush
  (tooth1,tooth2,tooth3...)
  )
)

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hey guys finally i solve it using 5 integers

and i dont know what u talking about cuz im new in c programming happy life

Quote:

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Originally Posted by eagle0eyes

hey guys finally i solve it using 5 integers

and i dont know what u talking about cuz im new in c programming happy life

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Code:

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#include <stdio.h>

int main(void) {
        int in, high, i;

        for (i=0;i<5;i++) {
                printf("Enter an integer: ");
                scanf("%d",&in);
                if (!i) high = in;        // the first loop
                else if (in > high) high = in;
        }

        printf("High: %d\n",high);

        return 0;
}

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