Assembler - binary

Can anyone help me out with this, b v.greatful. I'm trying to convert a given int to a binary number. I can output the data by dividing the num by 2 each time, e.g
10/2 = 0
5/2 = 1
2/2 = 0
1/2 =1
Program outputs 0101, but this has to be revesed so 1010. any ideas? Please!!!

void DecBinary(short int Num1)
{
short int Temp,Answer=0;

asm
{
mov ax,Num1;
mov Temp,ax;
Binary:
mov Answer,0;
mov bx,2;
xor ax,ax;
mov ax,Temp;
div bl;
mov bl,al //get whole no out of al
mov Temp,bx;

cmp ah,0;
jz NotNum;
jmp Next;

NotNum:
inc Answer;
}

asm
{
Next:
}

cout << Answer;

asm
{
cmp Temp,0;
jne Binary;
}
}

you could use push/pop to push the # on stack and then pop the # off when you need to. The would display in opposite order...that is just one way to do it

An example -

Code:

---

#include <cstdio>
using namespace std;

int main()
{
        int i = 123;
        char* form = "%d";
        _asm
        {
                mov eax,i
                mov ecx,32
bin:               
                mov ebx,eax
                and ebx,0x00000001
                push ebx
                shr eax,1
                loop bin
                mov ecx,32
print:       
                pop eax
                mov ebx,form
                push ecx
                push eax
                push ebx
                call printf
                add esp,8
                pop ecx
                loop print       
    }

        return 0;
}

---

Thanks for everyones help. Tried push and pop, works on win98 my system, but crashes on an nt system. can't understand why???
Anyway cheers.

What language is that (Assembly) and where can i read up on it?
I see it when I use my debug program.

Read this. It's pretty good. But, you have to come here to get it cause it is over the limit for a file size. http://www.flashdaddee.com/forums/sh...&threadid=1235

thx