How to display the values of a struct

I have yet another question!

How would you display the contents of struct?

Code:

---


typedef struct
{
    char track[20];
    char trackname[20];
    char artist[20];
    char genre[20];
}    song;

---

E.G, in the code above, to printf the contents of trackname?

A lecture provided:

Code:

---

          int x;

          for(x=0; x<10; x++)
          printf("%d", a[x]);

---

But I have little knowldege for adapting this. I tried changing the decimal into char and changing 'a[x]' into song, song.trackname and a few other variants, but have not been able to get it to work.

You display them the same way you display any other variable of the same type (the type you actually want to display; i.e.: an int, an array of char, etc.), you just prefix it with the structure instance:

Code:

---

printf( "foo.x = %d\n", foo.x );
printf( "foo.arrayofchar = %s\n", foo.arrayofchar ); /* assuming it's actually a valid string */

---

And so on...


Quzah.

Thanks, quzah, but what are you referring to with 'foo'?

I have tried entering those 'printf's in different way, but am unable to get them to work. I am very new to programming, so sorry if this seems really simple.

Foo is just supposed to be replaced by the name of the instance of your struct.

Thank you! This worked. I am really grateful :D