Derived class doesn't see base class function

I have a case where a derived class cannot see a virtual function defined in a public base class. The only explanation I can come up with is that C++ must have some kind of rule that says if you override a base class function with name "X", then you must override all base class functions having the same name. Is this a rule? See the following example:

Code:

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class base
{
public:
  virtual int func();
  virtual void func(int arg1,int arg2);       
  virtual void func2(int arg1,int arg2) { func(arg1,arg2); }
};

class derived : public base
{
public:
  // override func(), but not func(arg1,arg2)
  virtual int func();
};

void test
{
  derived xyz;
  int i = xyz.func();  // compiles OK
  xyz.func(1,2);          // compilation error: "func() does not take two arguments"
  xyz.func2(1,2); // compiles OK
};

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Quote:

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Originally Posted by ejubenville

The only explanation I can come up with is that C++ must have some kind of rule that says if you override a base class function with name "X", then you must override all base class functions having the same name. Is this a rule?

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Not quite. The rule is that a member name in the derived class hides members of the same name in the base class. You can bring in those hidden names by using a using declaration:

Code:

---

class derived : public base
{
public:
  using base::func;
  // override func(), but not func(arg1,arg2)
  virtual int func();
};

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Thanks!

The "using" declaration fixed the hidden names!