Cant solve the syntax error.

I have a program that is supposed to convert temperature i celcius to temperature in fehrenhiet. I get a syntax error on the line where the user is supposed to input the temperature in celcuis.

I cant seem to figure out what is wrong.
I keep getting error: error C2059: syntax error : ';'

Any help would be appreciated. Thanks in advance.

Code:

---

/* program to convert temperature in celcius
  to temerature in fahrenheit */


#include <iostream>

int c; //temperature in celcius
int f = (9/5 * (c)) + 32; //temperature in fahrenheit


int main()
{
        std::cout << "This program will convert your temperature in celcius to fahrenheit." "\n" "\n";
        std::cout << "What is your current temperature in celcius? ";
        std::cin >> c >>;                    //user inputs temerature in celcius
        std::cout << "Your temperature in fahrenheit is " << f << "." "  Now go be tell your friends."; 
                                              //program converts output to fahrenheit
        return (0);
}

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Code:

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change

std::cin >> c >>; 

to

std::cin >> c ;

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thanks for the help. why do you have to remove the second set of >> ?

Why do you want two? :)

You are putting what you type into "c" with the oparator >>.

I you put a second one it means you wanna put it again somewhere else, which is not the case.

This expression is wrong:

Code:

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int f = (9/5 * (c)) + 32; //temperature in fahrenheit

---

As far as C++ is concerned, 9/5 is equal to 0. So this expression is the same as:

Code:

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int f = 32;

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If you really want to stick to integer math, you can rewrite the expression this way:

Code:

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int f = 9 * c / 5 + 32;

---

This reorders the operations so that c is first multiplied by 9, then divided by 5. It's not precisely accurate due to integer round-off, but at least it doesn't output 32 all the time :)

Actually 9 / 5 equals 1.

The bigger problem is that the value of f is calculated before you give any input for c. You'll either need to move the calculation after the place where c gets a value, or turn it into a function instead.

alright. would the equation:

Code:

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int f = ((9/5) * (c)) + 32

---

work as well or does c++ read it still as 1? I'm at work now so I can't test the code out for myself now.

and when defining f i should do it after the user input instead when i declare the intergers?

Using another language, here's an example of integer versus float math:

Code:

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> ((9/5) * (26)) + 32
58
> ((9.0/5.0) * (26)) + 32
78.8

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In C as well, just by adding the ".0" to the 9 and 5, the results are more correct. In your case, assigning to f, you would get 78.

alright so to make my equation the most accurate i need to make it (9.0/5.0) when doing the conversion to fahrenhiet?

Quote:

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Originally Posted by brian75

alright so to make my equation the most accurate i need to make it (9.0/5.0) when doing the conversion to fahrenhiet?

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You need to change the variable type from an int to one that accepts floating point numbers.

Quote:

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Originally Posted by brian75

alright so to make my equation the most accurate i need to make it (9.0/5.0) when doing the conversion to fahrenhiet?

---

No, to make it most accurate, you'll need to use floats or doubles, and, your constants should be the same data type too.

so the beggining would want to look something like

Code:

---

/* program to convert temperature in celcius
  to temerature in fahrenheit */


#include <iostream>

float c; //temperature in celcius
float f = (9.0/5.0 * (c)) + 32.0; //temperature in fahrenheit

---

for the most accurate read out.

double f = (9.0/5.0 * (c)) + 32.0; //temperature in fahrenheit
9.0 is a double constant, thus the result is a double.
Otherwise you need to add f to the end of the constants to make them into floats.

Thank you for all your help everyone. I understand what was wrong now.

OK, Brian - that's great.

Now, tell us. WHO was most helpful here? Huh, HUH????

I will not answer that. Lol

Chicken. ;)