How to use getchar/gets to store chars in an array, all upper case, in a set amount?

Hello there. This is just part of error checking in a much larger program, where I have to use only getchar (if even) / gets to manipulate the array to only store uppercase A-Z characters, with min number of characters being 2, max 10. I guess I'm still not comfortable using these functions. No string library functions may be use. What I have so far is below. Any help would be highly appreciated, thanks in advance.

Code:

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#include <stdlib.h>
#include <stdio.h>

int main()
{
        char string[11]; /* gets will replace newline with null, so don't have to initialize
                                                string[10] to null*/
        int iochar;


        printf("Input string with uppercase A-Z characters, min 2 max 10:\n");
       
        while(iochar = getchar())
        {
                if(iochar >= 'A' && iochar <= 'Z')
                {
                gets(string);
                }
        }


        puts(string); /* testing string */

}

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What I have above doesn't do anything, I was just messing around with getchar and such. I tried to set the while loop as while(iochar = getchar() != '\n'), but that gave me some erroneous results. I've also tried setting an if statement to check for lowercase characters, and a printf call to tell the user that the string can't be lowercase, but it would be print that statement (can't be lowercase) every time a single lower case is found. This is just one part of my program that I can't seem to figure out...

suggestion

Code:

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#include <stdio.h>

int main (void)
{
    int      cnt = 0;
    const int max = 10;
    char      buf[11];
    int      ch;

    do {
        ch = getchar();
        if (ch >= 'A' && ch <= 'Z') {
            buf[cnt] = (char)ch;
            ++cnt;
        }
        if (ch == '\n') {
            break;
        }
    } while (cnt < max);
    buf[cnt] = '\0';
    puts(buf);

    return(0);
}

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