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Im guessing that it is a overide-able yes or no which is decided later.Code:virtual bool isCorrectAnswer(const std::string& answer) const = 0;
It checks if the value stored in answer is correct?
Probably not correct just wondering if anyone could explain
would this be considered a virtual function or constructor, im guessing function but then again it is assigned value of 0
(And yes I know the snippet is short)
The =0 makes the function pure, i.e. the containing class is abstract, as is any derived class unless it has an overriding definition of this function.
As for the semantics, you can only guess - the name and signature suggest that the function indeed checks the value of answer and returns whether it is correct, but that depends on the implementation. Of course, if this function does anything else, it's grossly misnamed.
Do a search for "pure virtual function" and you'll find your answer.
This is a pure virtual function..means if it is declared in a class ,the class becomes an abstract class that means you can't create any object of that class and it will enforce any subsequent classes those are derived from it to implement this function in their own class...Code:
virtual bool isCorrectAnswer(const std::string& answer) const = 0;
No, it won't. I worded my post very precisely.Quote:
it will enforce any subsequent classes those are derived from it to implement this function in their own class...
A class must define or inherit a concrete implementation of all its pure functions in order not to be abstract. However, if a class doesn't mind being abstract, it doesn't need to override its pure functions. There is a school of thought in object-oriented design (especially in C++) that says that only leaf classes of the hierarchy should ever be concrete.