C syntax: unsigned myvar;

Hi there,
just a quick question, what happens to variables of this kind in C compiler, defaults to system int?

I am just adapting the zlib compression example zpipe.c:

Code:

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int ret, flush;
unsigned have;
z_stream strm;
...
  have = CHUNK - strm.avail_out;
  if (fwrite(out, 1, have, dest) != have || ferror(dest)) {

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also just a guide on etiquette in posting on this forum, is there a syntax section for quickie questions like this?


thanks

Quote:

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unsigned have;

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If your referring to an unsigned int, it is basically an int which can only hold positive values.
The default in C is the signed int which allows you to hold both negative and positive values.

Quote:

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Originally Posted by Spidey

If your referring to an unsigned int

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You may have overlooked my question. I am referring to "unsigned" alone...What is it's intended meaning. if "unsigned" converts to "unsigned int" then which C syntax does this conform to?

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Originally Posted by lordmule

You may have overlooked my question. I am referring to "unsigned" alone...What is it's intended meaning. if "unsigned" converts to "unsigned int" then which C syntax does this conform to?

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The part of the C syntax that says that "unsigned" and "unsigned int" refer to the same type (in the same way that "int" and "signed int" refer to the same type).

excellent. thanks for that.

Quote:

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Originally Posted by lordmule

excellent. thanks for that.

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Note however that this does not stop you from saying unsigned char for example.