code output...

Hi,

In the program run below i get the output as follows:

Enter the string
Hackers have put us on hit list

Hackers
have
put
┼
─

I had a doubt regarding the output. The program has five scanf statements and i need to pass the string "Hackers have put us on hit list" when it prompts me. Now 1st scanf and printf shoudnt the output be "ckers" instead of Hackers . But in the fourth scanf it should take "us" as the input and 's' should be the output . Similarly for the fifth scanf it takes 'on' as the input but it gives something called as '-' as output.

insert

Code:

---

#include <stdio.h>
#include <conio.h>

void main(){

        printf("Enter the string");

        scanf("\n\r%s", &s[2]);
        printf("\n\r %s", &s[2]);

        scanf("\n\r%s", s);
        printf("\n\r%s", s);
       
        scanf("\n%s", &s);
        printf("\n%s", &s);
       
        scanf("\n%c", &s[1]);
        printf("\n%c", &s[1]);
       
        scanf("\n%c", &s);
        printf("\n%c", &s);
}

---

This can't possibly be the code you've tried to compile, because it doesn't.


Quzah.

This is what compiles on my machine

insert

Code:

---


#include <stdio.h>
#include <conio.h>

void main(){

        static char s[30];
        printf("Enter the string");

        scanf("\n\r%s", &s[2]);
        printf("\n\rHere %s", &s[2]);

        scanf("\n\r%s", s);
        printf("\n\r%s", s);
       
        scanf("\n%s", &s);
        printf("\n%s", &s);
       
        scanf("\n%c", &s[1]);
        printf("\n%c", &s[1]);
       
        scanf("\n%c", &s);
        printf("\n%c", &s);
       
}

---

Output is this:
Enter the string
Hackers have put us on hit list

Here Hackers
have
put
┼
─Press any key to continue . . .

You should consider reading the FAQ on how to read lines of text.

Cprogramming.com FAQ > Get a line of text from the user/keyboard (C)

Also, & means 'address of', so unless you're trying to actually display the address of something, you shouldn't be using it in printf.

Quzah.

@roann
Don't use void main ever. See the FAQ.

>Also, & means 'address of', so unless you're trying to actually display the address of something, you shouldn't be using it in printf

s is an array of chars, so '&(s[N])' in a printf with the '%s' format is correct.

Quote:

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Originally Posted by flexo87

s is an array of chars, so '&(s[N])' in a printf with the '%s' format is correct.

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Yes, but we see it first as...

Code:

---

printf("\n%s", &s);

---

Quzah.