a how-to :(

ok keep in mind i have done nothing advanced yet... only using basic strings, variables and outputing things to the screen and formatting them...

so here goes my question...

how do i make a program that splits an integer into two numbers eg
input 27
first digit is 2
second digit is 7

later on i have to modify it to aceept 3 digit numbers... now i am a bnit stumped... i dont want you to wrtie the whole thing for me... i just want a shove in the correct direction ;)

If the program accepts the integer as input from a user then it's easy. Simply read the input as a string and print each individual element to break it up.
Such as if the user enters 23, the array looks like this:
array[0] = 2;
array[1] = 3;
If you print array[0] then it will just output 2.

-Prelude

Use the modulus operator to split digits off the end. Use the place value of the digit to the left to modulus by. E.g, 27 % 10 = 7. The 2, value to the left of the 7, is in the tens place, so 10 was used to modulus by.

Code:

---

#include <iostream.h>
#include <lvp\string.h>

int main()

{
        String number;

        cout<<"Enter the two-digit number: ";
        cin>>number;
        cout<<"The first digit is "<<number[0]<<endl;
        cout<<"The second digit is "<<number[1]<<endl;
        return (0);
}

---

would this be correct?
my compiler does not have lvp/string and my book sasy i should be using it... i have msvc++ 4.0 wich is a bit old ;) and my book is for visual c++ 6.0

Quote:

---

Originally posted by salvelinus
Use the modulus operator to split digits off the end. Use the place value of the digit to the left to modulus by. E.g, 27 % 10 = 7. The 2, value to the left of the 7, is in the tens place, so 10 was used to modulus by.

---

oooo i think thats is what im suposed to do thankies ;)

we havent done arrays yet prelude but thx for the help ;) i have seen you helping a lot here and damn you deserve more credit than you get that is all :)

>you deserve more credit than you get that is all
I'm not here for credit, I'm here to help out :)

Funny how they ask you to come up with a solution for itoa when you haven't even covered basic arrays yet. I consider the itoa solution more advanced that arrays, but I'm not your instructor :D

-Prelude

yea, just take it as a string, i'll try it later myself, hehehe~~