how to return in void function();

i want to return begining in void function(); like return in main();
if is wrong number i want to ask till number right.
but my codes returning the main all the time i tryid

Quote:

---

return;

---

but still same. does anybody know how kan i return????

Code:

---

void function( )
{
    cout<<"WHAT IS THE NUMBER:";
    cin>>number;
    cin.get();

      for(int i=0; i<Size; i++)
        {
          if (NUMBER RIGHT)
              {
                  cout<<"\NUMBER RIHGT"<<endl;
                  cin.get();
                  break;
                }
          }
          if(NUMBER WRONG)
                {
                  cout<<"\WRONG NUMBER TRY AGAIN";
                  cin.get();
                }
}

---

You should name your function with a more descriptive name.

Anyway, it looks like what you want to do is to structure your loop such that you keep on requesting for input until the correct number is entered.

here is my real codes, if entry date and time not in the array i want to ask again till its find in array
so how im gonna do it????

Code:

---

void deleteAppointmentRecords( )
{
    bool flag = false;
        string deleteTime;
    int deleteday,deletemounth,deleteyear;
    int update;
    system("cls");  //clear screen
    cout<<"\nEnter Appointment Date you want to Delete: ";
    cin>>deleteday>>deletemounth>>deleteyear;
    cin.get();
    cout<<"\nEnter Appointment Time you want to Delete: ";
    cin>>deleteTime;
    cin.get();
    for(int i=0; i<currentSize; i++)
        {
            if (AppointmentList[i].appdate.day == deleteday &&
                AppointmentList[i].appdate.mounth == deletemounth &&
                AppointmentList[i].appdate.year == deleteyear &&
                AppointmentList[i].time == deleteTime)
                        {
                                update = i;
                                system("cls");  //clear screen
                                displayHeading( ); //display Appointment under heading
                                cout<<setw(20)<<AppointmentList[update].name;       
                                cout<<setw(23)<<AppointmentList[update].description;
                                cout<<AppointmentList[i].appdate.day;
                                cout<<"/"<<AppointmentList[update].appdate.mounth;
                                cout<<"/"<<setw(14)<<AppointmentList[update].appdate.year;
                                cout<<AppointmentList[update].time;
                                cout<<endl; //indicate user Appointmen will be Delete
                                cout<<"\n\nAppointmen Above will be Delete!!!\n"<<endl;
                                cout<<"\nPress any key to continue"<<endl;
                                cin.get();
                                              //delete Appointmen.
                                for(int k=update; k<=currentSize; k++)                 
                                AppointmentList[k] = AppointmentList[k + 1];

                                cout<<"\nAppointment Deleted!!!\n"<<endl;
                                cin.get();
                                flag = true;
                                currentSize -= 1; //update CurrentSize
                                break;
                    }
        }
                if(!flag)
                  {
                    cout<<"\n\nThere is No Appointment on this Date and Time!!!\n";
                    cout<<"\nEnter new Date and Time"<<endl;
                    cin.get();
                  }
}

---

Quote:

---

Originally Posted by pczafer

if entry date and time not in the array i want to ask again till its find in array
so how im gonna do it?

---

Write a function that finds an appointment in the array given a date and time. This function should either return the index of the appointment in the array, or say, currentSize if it is not found.

This way, your deleteAppointmentRecords can call this function. If the index returned is not currentSize, it would then call another function to delete the appointment by index. Otherwise, it would inform the user that no appointment exists at the given date and time, and thus request that the user input another date and time.

Quote:

---

Originally Posted by pczafer

if entry date and time not in the array i want to ask again till its find in array
so how im gonna do it?

---

Write a function that finds an appointment in the array given a date and time. This function should either return the index of the appointment in the array, or say, currentSize if it is not found.

This way, your deleteAppointmentRecords can call this function. If the index returned is not currentSize, it would then call another function to delete the appointment by index. Otherwise, it would inform the user that no appointment exists at the given date and time, and thus request that the user input another date and time.

If it is an integer you want to return, then change the void to int. Change the data type of the function declaration.