constant literal on LHS of conditional operator

I was just wondering - I see things like this a lot in other people's code:

Code:

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assert(0 <= index);

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And I was just wondering, why write it like this, when the meaning of:

Code:

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assert(index >= 0);

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...is so much more immediately apparent? Is there some reasoning behind this style, or are they just trying to be clever?

The idea is that if you make a mistake by performing an assignment instead:

Code:

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assert(0 = index);

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you would get a compile error.

The weakness is that since this only applies when an rvalue or const lvalue is involved, it is no guarantee of protection.

I see! Thanks.

I let the compiler find those errors for me.