check for y condition

let say i have two loops and i want to check if the varibles from one loop can evenly divided like this

Code:

---

for (y=1;y<5;y++){
    for (x=0;x<1000;x++){
            if (x%y==0){ printf("this one: %d \n",x)}}}

---

how can i make the(x%y==0) condition to be checked for every y condtion ranging from
1 to 5
i mean how can it make it find every number that can be eveny divided to all number ranging from 1 to 5
thanks

Presumably by putting a semicolon ";" after your printf statement. Once you have that syntactically correct, your if statement will check 4000 different cases (y 1,2,3,4; x from 0 to 999).

Code:

---

for (y=1;y<6;y++){
  for (x=0;x<1000;x++){
    if (x%y==0){
      printf("this one: %d \n",x);
  }
  }
}

---

If i understand you question correctly this should do it

edit:
as stated above, this will not check x=1000

Maybe you want something along these lines:

Code:

---

#include <stdio.h>

int main(void)
{
        int x,y;
        for (x=0;x<1000;x++)
        {
                int flag = 0;
                for (y=1;y<=5;y++)
                {
                        if (x%y)
                        {
                                flag = 1; /*found y that is not dividable by */
                                break;
                        }
                }
                if(flag == 0)
                {
                        /* x is dividable by all y */
                        printf("this one: %d \n",x);
                }
        }
        return 0;
}

---