Error in return variable.

Hey all. I am new to C and C++

I am doing a test program and it does not return the variable called input in the input2 function. any help would be great.

Code:

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#include <iostream>
using namespace std;
int input2(int input);

int main (int argc, char * const argv[]) {
    // insert code here...
//int input=0;
        int input;
        //input=0;
        input2(input);
       
   
       
        cout<<input;
        switch(input)
        {
                case 1:
                        printf("New Game");
                        break;
                case 2:
                        printf("Load Game");
                        break;
                case 3:
                        printf("high scores");
                        break;
                case 4:
                        printf("Quiting!");
                        break;
                default:
                        printf("Invalid Choice!");
                        break;
                       
        }
        getchar();

    return 0;
}

int input2(int input){
        //int input;
        //int test;
       
        std::cout << "Hello, World!\n";

        printf("\n\n1. Play Game\n");
        printf("2. Load\n");
        printf("3. High Scores\n");
        printf("4. Quit\n\n");
        printf("Selection:  ");
        cin>>input;
        cin.ignore();
       
        cout<<"\n"<<input<<"\n";
        //test==input;
        return input;
       
}

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You have to store the return variable somewhere, for example:

Code:

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int input = 9;
int root = 0;

root = get_square_root(input);

// now root is 3.

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Your current code uses an input parameter, but that doesn't change the variable in main. (There is a slightly more advanced technique called pass-by-reference that would do that, but that's not what you want here.) You don't need a parameter, you just need to use the return value.

Thanks.. That worked wonderfully.

It was so obvious. I don't know how I missed that.