recv data with sockets

Hi

Im not sure if this post should be in this board or the network programming board, anyway here is my question.

I am coding a server program with sockets on linux and when I got to the recv part I noticed a unexpected behaviour.

Here is the code for the recv data part:

Code:

---

//read some data
char recvBuf;
do
{
        error = recv(new_fd, &recvBuf, 1, 0);
        switch (error)
        {
        case -1:
                cout << "[ERROR] recieving data" << endl;
                recvBuf = '.';
                break;
        case 0:
                cout << "Connection to client was lost" << endl;
                recvBuf = '.';
                break;
        default:
                cout << recvBuf;
        }
} while (recvBuf != '.');

---

Now when I run this and connect to the server with telnet, the server waits until I press ENTER until it writes recvBuf to the screen. But if I press '.' the program ends without me pressing ENTER.

How can the text I type in telnet be saved and then printed, shouldn't the recvBuf be overwritten for every new data the server reads ?

Thanks for helping me understand this.

The output is probably buffered until it sees a newline.
Try cout.flush()

Thanks that worked.