C89 or C99

Hay there!

Not sure whether I should write C89 or C99... I've been using C89 so far.
How do I know when C99 is "available" for use? Does that only depend
on the compiler, or compiler and libraries etc?

I like that C99 has larger ints... other than that, I don't know much about
the differences... I know that

Code:

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for (int x = 0; ... ; ...) { ... }

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is allowed...
Any other interested things? Also, are "evil" functions such as atoi() still
available in C99? Have they deprecated anything at all?

I use gcc on Linux/FreeBSD and Mingw on Windows.

Quote:

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Originally Posted by talin

How do I know when C99 is "available" for use? Does that only depend
on the compiler, or compiler and libraries etc?

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Yes. Some compilers supports it, some does not. For example, GCC does support C99.

Quote:

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I like that C99 has larger ints... other than that, I don't know much about
the differences... I know that

Code:

---

for (int x = 0; ... ; ...) { ... }

---

is allowed...
Any other interested things?

---

Well...

Code:

---

int n = 5;
int myarray[n];

---

...works fine in C99.

Quote:

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Also, are "evil" functions such as atoi() still
available in C99? Have they deprecated anything at all?

---

Still available.

Quote:

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I like that C99 has larger ints... other than that, I don't know much about
the differences

---

Here's a quick summary:
http://home.datacomm.ch/t_wolf/tw/c/c9x_changes.html

and the current support status for gcc:
http://gcc.gnu.org/c99status.html

Quote:

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Originally Posted by Elysia

Well...

Code:

---

int n = 5;
int myarray[n];

---

...works fine in C99.

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Technically, I think what you describe is a compiler extension. In C99, it is required that you have "const int n = 5" - whilst gcc and MS also support you doing something like this:

Code:

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  int n;
  scanf("%d", &n);
  int array[n];

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--
Mats

Oh ho! So people have been using compiler extensions all this time!
Interesting.

Quote:

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Technically, I think what you describe is a compiler extension. In C99, it is required that you have "const int n = 5" - whilst gcc and MS also support you doing something like this:

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No, C99 really does allow for variable length arrays, though in the case of g++ it was ported over as a C++ compiler extension.

Ah, great. Thanks for all the answers!