n00b doing a Socket operation on non-socket

ok this is a real sockets n00b question...

My code...

Code:

if ( newFD = accept( scktFD, (struct sockaddr *)&client_addr, &sin_size ) == -1 ) {
		perror( "connection_listen: accept" );
		close( scktFD );
		exit( EXIT_FAILURE );
	}
	
	
	
	if (( send( newFD, "Hello world", 11, 0 )) == -1 ) {
		perror( "send" );
		close( newFD );
		exit( EXIT_FAILURE );
	}

the send always fails and returns the error "Socket operation on non-socket", when i print newFD it is 0.

I thought that was valid and i couldnt find a problem until i found this..

[NOT TO FIX]
60 * accept() returns a path name even if the connecting socket has closed
61 * in the meantime (BSD loses the path and gives up).
62 * accept() returns 0 length path for an unbound connector. BSD returns 16
63 * and a null first byte in the path (but not for gethost/peername - BSD bug ??)

in /net/unix/af_unix.c

Anyway I have no idea what is going wrong or if I am using accept the wrong way. Any pointers would be great.

Since fd 0 is usually stdin, sending to it is probably not a good idea.

> newFD = accept( scktFD, (struct sockaddr *)&client_addr, &sin_size ) == -1
Ah, good old precedence

if ( a = b == c ) is like saying
if ( a = ( b == c ) , call the func, compare with -1 and assign the boolean result to a

You want
if ( ( a = b ) == c ), call the func, assign to a and compare a with -1

wow salem, you did it again.. thanks