Sockets: IPv4 vs IPv6

Hello everyone in C Boards! I'm here to look again for answer or hints to help me accomplish what I need to do...

I'm writing a server with sockets (actually, a repository of files), and I have a code (see down). The code shouldn't care about IPv4 and IPv6. When a IPv6 interface connects to the server, everything is printed fine and the IP appears ok. Anyway, when a IPv4 connect to the repository the IP appears in a IPv6 style...

I know that they are the same address expressed in different ways, but I need it to print the IP as a IPv4 without the ::fffff: prefix...

Example:
Aceptada conexión de ::ffff:127.0.0.1
should print
Aceptada conexión de 127.0.0.1

The code:

Code:

	printf("Esperando conexiones por el puerto %s...\n",puerto);
	
	// Manejo de conexiones, etc
	while(1){
		sizeClient = sizeof(struct sockaddr_storage);
		socketClient = accept(socketId, (struct sockaddr *)&infoClient, &sizeClient);
		if(socketClient==-1){
			perror("aceppt");
			continue;
		}
		char s[INET6_ADDRSTRLEN];
		inet_ntop(infoClient.ss_family,
			  (void*)direccionIn((struct sockaddr_in *)&infoClient),
			  s, sizeof(s));
		printf("Aceptada conexión de %s\n", s);
		
		// Todo el código aqui
		// All the code here
		
		
		printf("Cerrando conexión de %s\n", s);
		close(socketClient);
	}

And the direccionIn:

Code:

void *direccionIn(struct sockaddr *sa) {
	// Si es IPv4
	if (sa->sa_family == AF_INET) {
		return &(((struct sockaddr_in*)sa)->sin_addr);
	}
	// Si es IPv6
	return &(((struct sockaddr_in6*)sa)->sin6_addr);
}

I've added another question... Anyone can give me some light on this? :S