finding files in a directory

I was just curious as to how I would run through the files in a directory and print out each file name.

thanks.

ls -a on the command line.

Are you looking to do this in a script or a compiled program?

starX
www.axisoftime.com

read the man page ($man scandir) for scandir. That should give you the info you want for your system.

Code:

int scandir (const char *dir, struct direct ***namelist, 
                                  int (*select) (const struct direct *),
                                  int (*compar) (const struct direct **, const struct direct **));

here's a rough example (notethat if select is passed a NULL arguement, all names under the directory are placed in the arrary of direct structures.

Code:

#include <sys/dir.h>
#include <sys/param.h>
#include <stdio.h>
#include <string.h>

extern int alphasort ();

char pathname[MAXPATHLEN];

int main ()
{
    int count, i;
    struct direct** files;

    strcpy (pathname, "/home/matt");
    count = scandir (pathname, &files, NULL, alphasort);
    if (count <= 0) {
        fprintf (stderr, "No files in the directory \n");
        exit (0);
    }
    printf ("Number of files = %d\n", count);
    for (i = 1; i < count + 1; ++i )
        printf ("%s\n", files[i-1]->d_name);

    return 0;
}

Let me know if you don't understand anything after you read the man page...

thanks to both of you!